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galina1969 [7]
3 years ago
12

How many valence electrons does the Lewis structure for a chlorine atom show?

Chemistry
1 answer:
Anettt [7]3 years ago
7 0
It has 7 i would show a picture but i cant 

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17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI
galina1969 [7]

Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

Explanation:

Given: M_{1} = 0.20 M,      V_{1} = 15.0 mL

M_{2} = 0.10 M,            V_{2} = ?

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula s follows.

M_{1}V_{1} = M_{2}V_{2}\\0.20 M ]times 15.0 mL = 0.10 M ]times V_{2}\\V_{2} = 30 mL

Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

4 0
2 years ago
Please help me with this honestly I'm clueless It's 7th science work......please help
olganol [36]
Hiii
3. describe the physical characters that can be observed: phenotype

6. a specific characteristic of an organism: trait

7. a section of DNA that provides instructions for specific traits: genes

8. allele expressed in the phenotype even if only one copy is present in the genotype: dominant

hope this helped :)
6 0
3 years ago
Read 2 more answers
What mass of ice can be melted with the same quantity of heat as required to raise the temperature of 3.00 mol H2O(l) by 50.0°C?
lions [1.4K]

Answer:

m=33.9g

Explanation:

Hello,

In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):

Q=nCp \Delta T=3.00mol*75.38\frac{J}{mol\°C} *50.0\°C\\\\Q=11307J

Afterwards, the mass of ice that can be melted is computed by:

Q=n \Delta _{fus}H

So we solve for moles with the proper units handling:

n=\frac{Q}{\Delta _{fus}H} =\frac{11307J}{6010\frac{J}{mol} } =1.88mol

Finally, with the molar mass of water we compute the mass:

m=1.88mol*\frac{18g}{1mol}\\ \\m=33.9g

Best regards.

7 0
3 years ago
How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?
ohaa [14]
Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
4 0
3 years ago
Read 2 more answers
Nitrogen gas and oxygen gas react according to the following equation: Energy + N2(g) + O2(g) Double arrow yields 2NO(g) Nitroge
Ann [662]
- increasing the concentration of N₂
- increasing the concentration of O₂
- decreasing the concentration of NO
- increasing the temperature

:)
7 0
3 years ago
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