Question

A mixture of CO(g) and H2(g) is pumped into a previously evacuated 2.0 L reaction vessel. The total pressure of the reaction system is 1.2 atm at equilibrium. What will be the total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 L at constant temperature

Answer 1

Answer:

The total equilibrium pressure of the system if the volume of the reaction vessel is reduced to 1.0 L at constant temperature = 2.4 atm

Explanation:

                   Total pressure of the system (P₁) = 1.2 atm at equilibrium

                   Volume (V₁) = 2.0 lit

                   If the volume of the reaction vessel is reduced to (V₂)= 1.0 lit

                   Pressure (P₂) ?

At constant temperature using Boyle's law

                        p₁v₁ = p₂v₂

            $or, P_{2}= \frac{P_{1}V_{1} }{V_{2} } = \frac{1.2 X2.0}{1.0}=2.4 atm$

Total pressure at equilibrium is equal to 2.4 atm.