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kkurt [141]
2 years ago
9

pls help with my with my homework, i started it but i’m stuck on the rest. if my answers that i already put are wrong pls let me

know

Physics
1 answer:
Alekssandra [29.7K]2 years ago
8 0

You are 100% right for question a and you have a good start on b!

Explanation:

For (ii) of part a, you could also say that since the friction force is in the opposite direction of the pushing force, that the friction is '-60N' The negative sign just shows the direction of friction relative to the pushing force. But for the magnitude the signs are not important.

For part b,

work done equals force × distance

w = F×d

In this case, the worker is pushing with 60 newtons, and the distance is 28m.

Therefore,

w = 60N×28m

w = 1680j

(Or 1.7kj)

Great job! You got most of it!

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w_f = 1.0345 rad/s

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                                    L_(c,i) = 0.5*M*R^2*0

                                    L_(c,i) = 0 kgm^2 /s

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                                    L_i = L_(p,i) + L_(c,i)

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                                  L_i = L_f

                                  5.2272 = w_f*(I_p + I_c)

                                  w_f =  5.2272/ R^2*(m + 0.5M)

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                                  w_f =  5.2272/ 0.44^2*(3.6 + 0.5*45)

                                  w_f =  5.2272/ 5.05296

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