What type of solution forms when lithium chloride dissolved in water?

1 answer:

6 0

Answer: strong electrolyte.

Justification:

1) Lithium chloride is an ionic compound, highly soluble in water.

2) This is the chemical equation:

LiCl(aq) → Li⁺ (aq) + Cl⁻ (aq)

3) Due to its ionic character and the small size of the ion Li⁺, LiCl dissociates almost completely, meaning the the solution is a strong electrolyte.

4) Electrolytes are solutions that carry electricity (the iones, charged species, are the carrierr of the electricity)

You might be interested in

CHEMISTRY HELP I don't understand this....please help? thank you in advance

Igoryamba

60 i believe i haven't did science in a while sorry if im wrong though... ._.

6 0

3 years ago

an irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 2 ml. The height of the wat

Phantasy [73]

The density of the stone is 5 g/cm³.

Mass = 25 g

Volume = 7 mL – 2 mL = 5 mL = 5 cm³

Density = mass/volume = 25 g/5 cm³ = 5 g/cm³

5 0

3 years ago

2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'

Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

$\displaystyle M_1V_1= M_2V_2$

Where M represents molarity and V represents volume.

Let the initial concentration and unknown volume be M₁ and V₁, respectively. Let the final concentration and required volume be M₂ and V₂, respectively. Solve for V₁:

$\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}$

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
$\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}$