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MrMuchimi
3 years ago
6

What type of solution forms when lithium chloride dissolved in water?

Chemistry
1 answer:
murzikaleks [220]3 years ago
6 0
Answer: strong electrolyte.

Justification:

1) Lithium chloride is an ionic compound, highly soluble in water.

2)  This is the chemical equation:

LiCl(aq) → Li⁺ (aq) + Cl⁻ (aq)


3) Due to its ionic character and the small size of the ion Li⁺, LiCl dissociates almost completely, meaning the the solution is a strong electrolyte.

4) Electrolytes are solutions that carry electricity (the iones, charged species, are the carrierr of the electricity)

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IDK THE ANSWER BUT I THINK I NEED HELP ON THIS ONE TO

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3 years ago
Describe how to use a transfer pipet to deliver 10.00 mL of liquid by placing the steps in the correct order.
nexus9112 [7]

This question is incomplete, the complete question is;

Describe how to use a transfer pipet to deliver 10.00 mL of liquid by placing the following steps in the correct order;

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

Answer:

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.  

Explanation:  

First of all, We use a suction device to suck up liquid into pipet. Then we will fill the pipet up to the 10 mL marks and will discard the initial two volumes of liquid and will take a final third volume. We will replace the bulb with index finger and will drain it by placing the tip of pipet at the wall of beaker and drain the liquid.

Arranged in the following steps correctly;

- Use a rubber bulb to suck liquid up past the 10.00 ml calibration mark.

- Discard the first two pipette volumes of the liquid to rinse the pipette.

- Suck up a third volume of liquid past the 10.00 ml calibration mark.

- Replace the bulb with your index finger and wipe excess liquid off the outside of the pipette.

- Place the tip of the pipette against the side of the beaker and drain the liquid from the pipette until the bottom of the meniscus reaches the calibration mark.

- Transfer the pipette to the receiving vessel.

- Drain the pipette by gravity while holding the tip against the side of the receiving vessel.

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3 years ago
Which of the following is the major argument against the use of nuclear power to generate electricity?
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3 years ago
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Answer:

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3 0
2 years ago
Assuming the volumes are additive, what is the [Cl−] in a solution obtained by mixing 297 mL of 0.675 M KCl and 664 mL of 0.338
Elden [556K]

<u>Answer:</u> The concentration of chloride ions in the solution obtained is 0.674 M

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}     .....(1)

  • <u>For KCl:</u>

Molarity of KCl solution = 0.675 M

Volume of solution = 297 mL

Putting values in equation 1, we get:

0.675=\frac{\text{Moles of KCl}\times 1000}{297}\\\\\text{Moles of KCl}=\frac{(0.675mol/L\times 297)}{1000}=0.200mol

1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion

Moles of chloride ions in KCl = 0.200 moles

  • <u>For magnesium chloride:</u>

Molarity of magnesium chloride solution = 0.338 M

Volume of solution = 664 mL

Putting values in equation 1, we get:

0.338=\frac{\text{Moles of }MgCl_2\times 1000}{664}\\\\\text{Moles of }MgCl_2=\frac{(0.338mol/L\times 664)}{1000}=0.224mol

1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion

Moles of chloride ions in magnesium chloride = (2\times 0.224)=0.448mol

Calculating the chloride ion concentration, we use equation 1:

Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles

Total volume of the solution = (297 + 664) mL = 961 mL

Putting values in equation 1, we get:

\text{Concentration of chloride ions}=\frac{0.648mol\times 1000}{961}\\\\\text{Concentration of chloride ions}=0.674M

Hence, the concentration of chloride ions in the solution obtained is 0.674 M

5 0
3 years ago
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