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2 years ago

A football has a mass of 2 kg and it accelerates at 20 m/s2. What is its force? (You can use a calculator)

Physics

2 answers:

attashe74 [19]2 years ago

8 0

10 mps is the answer

kap26 [50]2 years ago

6 0

Answer:

The answer is 40mps.

Explanation:

1. Force = (mass of an object) x (acceleration)

2. Force = ( "has a mass of 2 kg" ) x ( "accelerates at 20 m/s^2" )

3. Plug the numbers into the formula

4. F = 2 x 20

5. F = 40 mps

<em>Hope I helped!! Please mark me branliest :)</em>

- sophi

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A circuit contains two 2,000 resistors connected in parallel. What is the total resistance of the circuit?

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RT = R1 R2/ R1 + R2

R1 = R2 = 2k ohm

RT = R/2 = 2k/2 = 1k ohm

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2 years ago

We tend to feel less _____ when more people are around to help out. compassionate conformity responsible no answer is correct

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Responsible because we feel less stressed when others help out with our responsibilities.

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3 years ago

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3 years ago

You are driving to the grocery store at 18 m/sm/s. You are 160 mm from an intersection when the traffic light turns red. Assume

inysia [295]

Answer:

part(a) 151 m

part(b) 1.073 m/s2

part(c) 16.7 secs

Explanation:Firstly the person applied brakes 0.5 secs after seeing the red light hence the distance traveled during this time is

d=v*t

d=18*0.5

d=9m

For part (a)

I have corrected this question and now

The person was 160m from the intersection before applying the brakes as he traveled 9m before the brakes

He is now 151 m from intersection as

s=160-9

s= 151 m

part (b)

As it is given that velocity of the car is 0 at the intersection so we use this information in kinematic equation

$v^2=u^2+2as$

here u=18m/s and s=151

$0=18^2+2a*151\\302a=-324\\a=-1.073 m/s^2$

To calculate time we can use the acceleration equation

$a=\frac{v-u}{t} \\t=\frac{v-u}{a}\\t=18/1.073\\t=16.77 secs$

6 0

2 years ago

Outside the space shuttle, you and a friend pull on two ropes to dock a satellite whose mass is 700 kg. The satellite is initial

MaRussiya [10]

Answer:

your friend did a work of 1717.34 J

Explanation:

The sum of the work made by your friend and you is equal the change in the kinetic energy, so:

$W_a+W_b=\frac{1}{2}mv_f^{2}-\frac{1}{2}mv_i^{2}$

Where $W_a$ is the work that you did, $W_b$ is the work that your friend did, m is the mass of the satellite and $v_f$ and $v_i$ are the final and initial speeds

Additionally the work that you did is equal to:

$W_a=F.s$

Where F and s are vectors. So, the vector s that said the displacement is calculated as:

s = <2.3, 2.6, -11.8> - <3.3, -1.6, 2.0>

s = <-1 , 4.2 , -13.8>

Therefore, $W_a$ is:

$W_a=.$

$W_a=(-400*-1)+(500*4.2)+(250*-13.8)\\W_a=400+2100-3450\\W_a=-950$

Then, replacing the values on initial equation and solving for $W_b$ , we get:

$-950+W_b=\frac{1}{2}(700)(6.18)^{2}-\frac{1}{2}(700)(6)^{2}\\-950+W_b=767.24\\W_b=767.24+950\\W_b=1717.34J$

Finally, your friend did a work of 1717.34 J

3 0

2 years ago