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vichka [17]
3 years ago
13

Want brainly?? Answer this question correctly and I got you.

Physics
2 answers:
WARRIOR [948]3 years ago
8 0

Answer:

Divergent boundary. hope it helps

matrenka [14]3 years ago
4 0

Answer:

divergent

Explanation:

That is when two plate boundaries slide apart

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A 1.5 kg frictionless pendulum is released from point A at an angle θ of 35 degrees. The speed of the pendulum at point C is 3.4
sergeinik [125]

The length of the pendulum is 3.3 m.

The given parameters:

  • Mass, m = 1.5 kg
  • Angle, θ = 35⁰
  • Speed, v = 3.4 m/s

<h3>What is principle of conservation of energy?</h3>
  • The principle of conservation of energy states that, the total energy of a system is always conserved.

P.E = K.E

mgh = ¹/₂mv²

gh = ¹/₂v²

g(L - Lcosθ) = ¹/₂v²

gL(1 - cosθ) = ¹/₂v²

L = \frac{v^2}{2g(1- cos\theta)} \\\\L = \frac{(3.4)^2}{2\times 9.8(1 - cos35)} \\\\L = 3.28 \ m\\\\L = 3.3 \ m

Thus, the length of the pendulum is 3.3 m.

Learn more about length of pendulum here: brainly.com/question/8168512

3 0
3 years ago
Explain why it is important that the balloon is made from an electrical insulator.
aleksandr82 [10.1K]

Explanation:

object made of rubber, such as the ballons are elecrical insulators, meaning that they resist electric charges flowing through them..

when the ballon has been rubbed enough times to gain a sufficient negative charge, it will be attracted to the wall

8 0
3 years ago
Jessie draws a ray diagram to show how an image of a candle is produced by a concave mirror when the candle is placed in front o
irina1246 [14]
There are two rules of reflection for the concave mirror:
1)<span>Any incident ray traveling parallel to the principal axis on the way to the mirror will pass through the focal point upon reflection.
2)</span><span>Any incident ray passing through the focal point on the way to the mirror will travel parallel to the principal axis upon reflection.
Also, keep in that for concave mirror center of curvature is 2f.
Using these two rules we can construct the image. 
You should always use these two "special" rays, I will mark then 1 and 2 on the picture.
From the picture, we can see that if you place the object between the focus and vertex you get the virtual image.
The answer is: object should be between the focal point and the vertex</span>

8 0
3 years ago
Read 2 more answers
Two guitars are playing together producing a beat frequency. The first guitar is playing at a frequency of 867 Hz and the beat i
IgorLugansk [536]

Answer:

892 Hz or 842 Hz

Explanation:

Given

The frequency of first guitar is 867 Hz

Beat is produced for every 0·04 s

∴ Beat has a time period of 0·04 s

<h3>Beat frequency is defined as the inverse of the time period of the beat </h3>

Beat frequency = 1 ÷ (Time period) = 1 ÷ 0·04 = 25 Hz

Let the frequency of the second guitar be f Hz

<h3>Beat frequency is defined as the absolute difference between the two frequencies</h3>

∴ Beat frequency = (867 - f) or (f - 867)

First case

25 = 867 - f ⇒ f = 842 Hz

Second case

25 = f - 867 ⇒ f = 892 Hz

∴ Possible frequencies of second guitar could be 892 Hz or 842 Hz

4 0
3 years ago
How fast must an object move before its length appears to be contracted to one-fourth its proper length? (Give your answer in te
Tresset [83]

Answer:

<em>0.97c</em>

<em></em>

Explanation:

From the relativistic equation for length contraction, we have

l = l_{0}\sqrt{1 - \beta }

where

l is the final length of the object

l_{0} is the original length of the object before contraction

β = v^{2} /c^2

where v is the speed of the object

c is the speed of light in free space = 3 x 10^8 m/s

The equation can be re-written as

l/l_{0} = \sqrt{1 - \beta }

For the length to contract to one-fourth of the proper length, then

l/l_{0} = 1/4

substituting into the equation, we'll have

1/4 = \sqrt{1 - \beta }

substituting for β, we'll have

1/4 = \sqrt{1 - v^2/c^2 }

squaring both side of the equation, we'll have

1/16 = 1 - v^2/c^2

v^2/c^2 = 1 - 1/16

v^2/c^2 = 15/16

square root both sides of the equation, we have

v/c = 0.968

v = <em>0.97c</em>

3 0
3 years ago
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