Answer:
Answer:
28.025 Nm
Explanation:
Angular acceleration, α = 29.5 rad/s^2
oment of inertia, I = 0.95 kg m^2
The torque is defined as
τ = I x α
τ = 0.95 x 29.5
τ = 28.025 Nm
Thus, the torque is 28.025 Nm.
Explanation:
A. because everything is balanced.
To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.
We know that by Hooke's law

Where,
k = Spring constant
x = Displacement
Re-arrange to find k,




Perioricity in an elastic body is defined by

Where,
m = Mass
k = Spring constant


Therefore the period of the oscillations is 0.685s
Answer:
sorry I don't know but I hope you get a answer soon
Answer:
vf = √(vi²+2*(F/m)*D)
Explanation:
Given
Mass of the particle: M
Initial speed of the particle: vi
Force: F
Distance: D
We can apply the formula
F = M*a ⇒ a = F/m
then we use the equation
vf = √(vi²+2*a*D)
⇒ vf = √(vi²+2*(F/m)*D)