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Marta_Voda [28]
3 years ago
9

A cantilever beam of length L = 70 in is made from two side-by-side structural-steel channels of size 3 in weighing 5.0 lbf/ft.

The beam supports a uniform external distributed load of w = 6 lbf/in and a point load of F = 170 lbf at the end. Including the weight of the channels, use Castigliano's theorem to find the magnitude of deflection at A.
Engineering
1 answer:
natali 33 [55]3 years ago
6 0

Answer:

of 5 lb/ft and a concentrated service live load at midspan. .... length = 12 feet) to support a uniformly distributed load. Taking ... w 7..'{ 'f.- ~ s-·. 344 ft-kip. Fy : s-o ks I. 299 ft-kip. Li.. ::::- I 2.. }-t-. 150 ft-kip ..... The concrete and reinforcing steel properties are ... Neglecting beam self-weight . and based only on the ...... JI : Lf, 2. l.. ;VI.

Explanation:

You might be interested in
The distribution of actual weights of 8‑ounce wedges of cheddar cheese produced at a dairy is Normal, with mean 8.1 ounces and s
s344n2d4d5 [400]

Answer:

sampling distribution

Explanation:

Sampling distribution is distribution of multiple samples' satistics of a population.

3 0
3 years ago
Five kilograms of air at 427°C and 600 kPa are contained in a piston–cylinder device. The air expands adiabatically until the pr
son4ous [18]

Answer:

The entropy change of the air is 0.240kJ/kgK

Explanation:

T_{1} =427+273K,T_{1} =700K\\P_{1} =600kPa\\P_{2} =100kPa

T_{2}  is unknown

we can apply the following expression to find T_{2}

-w_{out} =mc_{v} (T_{2} -T_{1} )

T_{2} =T_{1} -\frac{w_{out } }{mc_{v} }

now substitute

T_{2} =700K-\frac{600kJ}{5kg*0.718kJ/kgK} \\T_{2}=533K

To find entropy change of the air we can apply the ideal gas relationship

Δs_{air}=c_{p} ln\frac{T_{2} }{T_{1} } -Rln\frac{P_{2} }{P_{1} }

Δs_{air} =1.005*ln(\frac{533}{700})-0.287* in(\frac{100}{600} )

Δs_{air} =0.240kJ/kgK

4 0
3 years ago
Your program will be a line editor. A line editor is an editor where all operations are performed by entering commands at the co
soldier1979 [14.2K]

Answer:

Java program given below

Explanation:

import java.util.*;

import java.io.*;

public class Lineeditor

{

private static Node head;

 

class Node

{

 int data;

 Node next;

 public Node()

 {data = 0; next = null;}

 public Node(int x, Node n)

 {data = x; next =n;}

}

 

public void Displaylist(Node q)

 {if (q != null)

       {  

        System.out.println(q.data);

         Displaylist(q.next);

       }

 }

 

public void Buildlist()

  {Node q = new Node(0,null);

       head = q;

       String oneLine;

       try{BufferedReader indata = new

                 BufferedReader(new InputStreamReader(System.in)); // read data from terminals

                       System.out.println("Please enter a command or a line of text: ");  

          oneLine = indata.readLine();   // always need the following two lines to read data

         head.data = Integer.parseInt(oneLine);

         for (int i=1; i<=head.data; i++)

         {System.out.println("Please enter another command or a new line of text:");

               oneLine = indata.readLine();

               int num = Integer.parseInt(oneLine);

               Node p = new Node(num,null);

               q.next = p;

               q = p;}

       }catch(Exception e)

       { System.out.println("Error --" + e.toString());}

 }

public static void main(String[] args)

{Lineeditor mylist = new Lineeditor();

 mylist.Buildlist();

 mylist.Displaylist(head);

}

}

7 0
3 years ago
How can I solve 23.5 million Nona meters to millimeters using no calculator because I have to show my work
lozanna [386]

Answer:

its so simple. u must mind some formulas.

Explanation:

mili->10^(-3)

micro->10^(-6)

nano->10^(-9)

so write the exact number and move "." to left or right depend question.

in this one:

23.5 is 23500000.0 nano with a default dot at the end

for turning to mili u must move the dot 6 steps to left so it will be: 23.5 milimeter.

6 0
3 years ago
Explain the Corona discharge?​
rosijanka [135]

Answer:

• Corona discharge means <u> </u><u>neutralization</u><u> </u><u>of</u><u> </u><u>charge</u><u> </u><u>action</u><u> </u><u>at</u><u> </u><u>a</u><u> </u><u>sharp</u><u> </u><u>point</u>

example; a pear shaped conductor, lightening conductor, van de graaf generator.

Explanation:

• In corona discharge, When a sharp conductor is placed somewhere in open space. The charges of opposite chrage attract the opposite ions in the air around that conductor.

• This increases the charge density and electric field intensity at the sharp point, this neutralises the charge at sharp point hence a discharge known as corona discharge occurs.

.

8 0
3 years ago
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