Answer:
true
Explanation:
newton's third law of motion states that if body A exerts a force on the body B, then body B will exert an equal and opposite force on body A,
this is called action reaction pair
hope this helps
Answer:
The product of the decay its Sulfur-32
Explanation:
Phosphorus-32 ( lets write it
, where the number above its the atomic mass and the number below the atomic number) decays turning a neutron into a proton and emitting radiation on the form of a electron. This is the beta minus decay, and, actually, an electronic antineutrino its also produced. We can write this decay for an X isotope with a Y isotope produced as:
![_{Z}^{A}X \to _{Z+1}^{A}Y + e^- + \bar{\nu_e}](https://tex.z-dn.net/?f=_%7BZ%7D%5E%7BA%7DX%20%5Cto%20_%7BZ%2B1%7D%5E%7BA%7DY%20%2B%20e%5E-%20%2B%20%5Cbar%7B%5Cnu_e%7D)
where
its the electron, and
the electronic antineutrino . We can see that the atomic number increases by one (cause a proton it produced and retained into the nucleus), and the atomic mass is approximately the same (there is a small difference between the neutron and proton mass, but its very small).
So, Phosphorus-32 (atomic number 15) will turn to an element with atomic number 16, and atomic mass 32, as:
.
.
The Y isotope must have an atomic number of 16 and an atomic mass of 32. The element with atomic number 16 its Sulfur (S), so, our decay its
.
and the product of such decay its Sulfur-32
Given:
L = 1 mH =
H
total Resistance, R = 11 ![\Omega](https://tex.z-dn.net/?f=%5COmega)
current at t = 0 s,
= 2.8 A
Formula used:
![I = I_{o}\times e^-{\frac{R}{L}t}](https://tex.z-dn.net/?f=I%20%3D%20I_%7Bo%7D%5Ctimes%20e%5E-%7B%5Cfrac%7BR%7D%7BL%7Dt%7D)
Solution:
Using the given formula:
current after t = 0.5 ms = ![0.5\times 10^{-3} s](https://tex.z-dn.net/?f=0.5%5Ctimes%2010%5E%7B-3%7D%20s)
for the inductive circuit:
![I = 2.8\times e^-{\frac{11}{1\times 10^{-3}}\times 0.5\times 10^{-3}}](https://tex.z-dn.net/?f=I%20%3D%202.8%5Ctimes%20e%5E-%7B%5Cfrac%7B11%7D%7B1%5Ctimes%2010%5E%7B-3%7D%7D%5Ctimes%200.5%5Ctimes%2010%5E%7B-3%7D%7D)
![I = 2.8\times e^-5.5](https://tex.z-dn.net/?f=I%20%3D%20%20%202.8%5Ctimes%20e%5E-5.5)
I =0.011 A
It would be a high pitched sound. Hope this helps.