Answer:you use / this
Explanation: for exmp 1/4 x 1/9=
Answer:
(a)
(b) 43.45 m
(c) 12.58 m
Explanation:
By applying newton's law on car,
where is the friction force and m is mass, a is acceleration
a = acceleration of car
(b)
From kinematic equation
but u=0 hence
and making s the subject
(c
From the kinematic equation
Answer:
the water level was shallow beach, then it rose to deep sea, then the water receded to a beach
Answer:
Minimum stopping distance = 164.69 ft
Explanation:
Speed of car = 35.6 mi/hr = 15.82 m/s
Stopping distance = 40.8 ft = 12.44 m
We have equation of motion
v² = u² + 2as
0²=15.82²+ 2 x a x 12.44
a = -10.06 m/s²
Now wee need to find minimum stopping distance, in ft, for the same car moving at 71.5 mi/h.
Speed of car = 71.5 mi/h = 31.78 m/s
We have
v² = u² + 2as
0² = 31.78² - 2 x 10.06 x s
s = 50.2 m = 164.69 ft
Minimum stopping distance = 164.69 ft