Explanation:
Given that,
The frequency of electromagnetic spectrum is ![2.73\times 10^{16}\ Hz](https://tex.z-dn.net/?f=2.73%5Ctimes%2010%5E%7B16%7D%5C%20Hz)
(A) Let the wavelength of this radiation is
. We know that,
![c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{2.73\times 10^{16}}\\\\\lambda=1.09\times 10^{-8}\ m](https://tex.z-dn.net/?f=c%3Df%5Clambda%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7Bc%7D%7Bf%7D%5C%5C%5C%5C%5Clambda%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B2.73%5Ctimes%2010%5E%7B16%7D%7D%5C%5C%5C%5C%5Clambda%3D1.09%5Ctimes%2010%5E%7B-8%7D%5C%20m)
So, the wavelength of this radiation is
.
(B) Let E is the energy associated with this radiation. Energy of an electromagnetic radiation is given by :
![E=hf](https://tex.z-dn.net/?f=E%3Dhf)
h is Planck's constant
![E=6.63\times 10^{-34}\times 2.73\times 10^{16}\\\\E=1.8\times 10^{-17}\ J](https://tex.z-dn.net/?f=E%3D6.63%5Ctimes%2010%5E%7B-34%7D%5Ctimes%202.73%5Ctimes%2010%5E%7B16%7D%5C%5C%5C%5CE%3D1.8%5Ctimes%2010%5E%7B-17%7D%5C%20J)
1 kcal = 4184 J
It means,
![1.8\times 10^{-17}\ J=\dfrac{1}{4184}\times 1.8\times 10^{-17}\\\\=4.3\times 10^{-21}\ \text{kcal}](https://tex.z-dn.net/?f=1.8%5Ctimes%2010%5E%7B-17%7D%5C%20J%3D%5Cdfrac%7B1%7D%7B4184%7D%5Ctimes%201.8%5Ctimes%2010%5E%7B-17%7D%5C%5C%5C%5C%3D4.3%5Ctimes%2010%5E%7B-21%7D%5C%20%5Ctext%7Bkcal%7D)
Hence, this is the required solution.
1 atmosphere = 14.7 lb/in
So to convert lb/in to atmosphere, just divide by 14.7.
28.5 / 14.7 = 1.94 atmospheres.
Looking at both reactions, we can see that the combustion of carbon, graphite or diamond, leads to the formation of carbon dioxide and energy. Since energy is a product of the reaction, we known that this is an exothermic reaction. The value of the change in enthalpy, ΔH, will be negative.
A negative value of ΔH in each exothermic reaction suggests that the carbon dioxide product is at a lower energy than the reactants. And since more energy is released in the combustion of diamond compared to graphite, we know that diamond has a higher internal energy than graphite.
Answer:
See explanation and image attached
Explanation:
Now, we have chosen the alkene 1-propene in our example.
In the first reaction of 1-propene with HBr, the reaction proceeds by ionic mechanism leading to the formation of 2-bromo propane.
In the second reaction of 1-propene with the bromine molecule, the first step is the formation of the brominium cation which is a cyclic intermidiate followed by the addition of Br^- yielding the 1,2- dibromopropane product