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ziro4ka [17]
4 years ago
12

Which is the strongest type of intermolecular force between solute and solvent in br2(l) in ccl4(l)?

Chemistry
1 answer:
sukhopar [10]4 years ago
6 0
Br₂ is a completely non-polar molecule as it has two bromine atoms of equal electronegativities, which results in no dipole moment. CCl₄ is also a completely non-polar molecule. Although, there is a dipole moment for every C-Cl bond in the molecule. But since the structure of CCl₄ is tetrahedral, this results in every dipole cancelling out which provides an overall molecule with no dipole moment.

Since both molecules are non-polar with no net dipole moments, and there are no hydrogens capable of hydrogen-bonding, the only intermolecular forces between the two species are van der waals forces, more specifically London dispersion forces.

The London dispersion forces are instantaneous dipole moments created when the two molecules interact which causes a very weak attraction.
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The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem
Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

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R = gas constant

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R=0.08205L.atm/mol.K

R=8.3145L.kPa/mol.K

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3 years ago
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3 years ago
If 60.0 ml of a 1.5 m hcl solution is put into a flask and diluted with water to make 2.0 l of solution
77julia77 [94]

Answer:

The molarity of the diluted HCl solution: <u>M₂ = 0.045 M</u>  

Explanation:

To find- the molarity of the diluted HCl solution (M₂)

Given- <u>For original HCl solution</u>-

Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L          (∵ 1L = 1000 mL)

Then this original solution is diluted to a volume of 2 L

Thus <u>for the diluted HCl solution</u>-  

The Volume of the diluted HCl solution: V₂ = 2 L

<u>So the Molarity of the diluted HCl solution (M₂) can be calculated by the </u><u><em>dilution equation:</em></u>

M_{1}\times V_{1} = M_{2}\times V_{2}

\Rightarrow M_{2} = \frac{M_{1}\times V_{1}}{V_{2}}

\Rightarrow M_{2} = \frac{1.5 M\times 0.06 L}{2 L} = 0.045 M

<u>Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M</u>

7 0
3 years ago
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