<h2>♨ANSWER♥</h2>
In coordination chemistry,
A coordinate covalent bond also known as a <em>dative bond, dipolar bond, or coordinate bond</em> is a kind of two-center, two-electron covalent bond in which the two electrons derive from the same atom. The bonding of metal ions to ligands involves this kind of interaction.
<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>
_♡_<em>mashi</em>_♡_
The Gulf Stream, warm current in the Atlantic
The state of the balloon:
When the balloon is submerged in the beaker, the amount of water in the beaker will get reduced.
What is Osmosis:
Based on the concentration of solutes on both sides of the membrane, water will flow through a permeable membrane in a specific direction.
<u><em>Hypertonic solution:</em></u>
It means that there are more solutes present in the surrounding environment than in the cell itself.
<u><em>Hypotonic solution:</em></u>
In a hypotonic solution, the concentration of solutes inside the cell is higher than that outside the cell.
- When comparing two solutions, the one with the larger solute concentration is hypertonic, and the one with the lower solute concentration is hypotonic. Isotonic solutions have an identical solute concentration.
- While the solution in the beaker is hypertonic, Meaning that will draw water molecules out of the cell. As water molecules move from a location of high water potential (dilute solution) to a region of reduced water potential (10% glucose solution), the water from the 5% glucose solution will flow into the 10% one (concentrated solution)
- This is the reason why the amount of water decreases when the balloon is submerged in the beaker.
Learn more about the glucose solution and permeability here,
brainly.com/question/14748422
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Answer:
The equation is already balanced. There's an equal number of materials on each side of the equation.
<span>1.05 g/ml * 1000 ml = 1050g/l because of 1g/ml = 1 kg/l
so, a/q
mass of 4.7 l of whole blood in pound =
4.7 * 1050 = 4935 g
so in pound
4935g = 10.87981p</span>