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Kaylis [27]
3 years ago
14

Gretchen wants to run a test to discover whether glass, copper, wood, or plastic conduct electricity. She sets up a circuit conn

ecting a battery to a light bulb, with a small gap she will use to test the conductivity of the different substances. One at a time, she connects the circuit with the chosen test material, and records whether or not the light bulb comes on. The variables in this experiment are
Chemistry
2 answers:
bagirrra123 [75]3 years ago
5 0
Battery,and i think the light bulb because it depends how much energy the light bulb needs
Bess [88]3 years ago
5 0

The plastic, wood, copper, and glass are the variables. The variables in an experiment are the things we can change and then test.

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If you had an aqueous mixture that contained Ag+ , K+ , and Pb2+ cations, how many different solids could precipitate if a chlor
SCORPION-xisa [38]

Answer:

Two, KCl and PbCl₂.

Explanation:

Hello!

In this case, since the addition of chloride ions promote the following three ionic reactions:

Ag^+(aq)+Cl^-(aq)\rightleftharpoons AgCl(s)\\\\K^+(aq)+Cl^-(aq)\rightleftharpoons KCl(aq)\\\\Pb^{2+}(aq)+Cl^-(aq)\rightleftharpoons PbCl_2(s)

We can infer that both silver chloride and lead (II) chloride are precipitated products as their Ksp are 6.56x10⁻⁴ and 1.59x10⁻⁵ respectively, which means they are merely soluble in water.

Best regards!

3 0
3 years ago
When 32 grams of aluminum react, the actual yield is 105.5 grams, what is the percent yield?
user100 [1]

Answer:

329.7%

Explanation:

Percent Yield = Actual Yield/ Theoretical Yield x 100%

Percent Yield = 105.5g/32 x 100% = 329.69 ≈ 329.7 %

5 0
3 years ago
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
3 years ago
How would your experimental formula of magnesium chloride “MgClx” have been affected if
aksik [14]
The compound is used in medicine as a source of magnesium ions, which are essential for many cellular activities. Magnesium chloride has also been used as a cathartic and in alloys. To low
6 0
3 years ago
the daily dose of ampicillin for the treatment of an ear infection is 115 mg/kg of body weight. what is the daily dose for a 43-
Lorico [155]
M=43lb = 19,5kg

If 115mg --------- is for --------- 1kg
                             so
    x        ---------- is for --------- 19,5kg

x = 19,5kg * 115mg / 1kg
x = 2242,5 mg
6 0
3 years ago
Read 2 more answers
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