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umka21 [38]
3 years ago
14

What is the change called from a solid to a gas​

Chemistry
1 answer:
nadya68 [22]3 years ago
8 0

Answer: Sublimation

Explanation: The process of a solid becoming a gas is called sublimation.

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Jill is making lemonade. She mixes together some water, lemon juice, and sugar. The lemonade is classified as a(n) _________. A)
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Hello, Thanks for making your post on brainly!

I would say the best answer is C)Mixture

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8 0
3 years ago
Read 2 more answers
How many moles of Co2 are produced when 0.2 moles of sodium carbonate reacts with excess HCl
Pie
To determine the number of moles of carbon dioxide that is produced, we need to know the reaction of the process. For the reaction of HCl and sodium carbonate, the balanced chemical equation would be expressed as:

2HCl + Na2CO3 = 2NaCl + H2O + CO2

From the initial amount given of sodium carbonate and the relation of the substances from the balanced reaction, we calculate the moles of carbon dioxide as follows:

0.2 moles Na2Co3 ( 1 mol CO2 / 1 mol Na2Co3 ) = 0.2 moles CO2

Therefore, the amount in moles of carbon dioxide that is produced from 0.2 moles sodium carbonate would be 0.2 moles as well.
5 0
3 years ago
What are parts of the nervous system
Vlad1618 [11]

Answer:

the brain and the spinal cord are the two main parts.

6 0
3 years ago
Which element consists of positive ions immersed in a “sea” of mobile electrons
worty [1.4K]

Answer:

Explanation:

Nickel is the only metal listed. Metal elements have metallic bonds between the metal atoms. Positive metal ions in a sea of electrons.

4 0
3 years ago
Determine the number of valence electrons for the following: [kr] 5s2 4d6
wlad13 [49]

Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).

Explanation:

This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7

Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4

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