Haploid number of chromosomes and gamete cells.
Answer:
So X has an atomic mass of 55.05 u, and is probably Mn
Explanation:
<u>Step1: </u>Balance the equation
XI2 +Cl2 → XCl2 + I2
<u>Step2:</u> find the molar mass of the compounds
<em><u>Compounds : </u></em>
X ⇒ Molar mass = M
XI2 ⇒ Molar mass = M + 2*126.9 u
XCl2 ⇒Molar mass = M + 2*35.45u
⇒For 1 mole XI2 we have 1 mole Cl2 reacting , as well as 1 mole XCl2 and 1 mole I2 produced.
<u>Step 3:</u> Calculating the atomic mass
(1.383g * XI2) / (M + 2*126.90 u) = (0.564g * XCl2) / ( M + 2 * 35.45u)
1.383 (M + 2 *35.45 u )= 0.564 (M + 2*126.90)
1.383M + 98.0547 = 0.564 M + 143.1432
1.383 M - 0.564 M =143.1432 - 98.0547
0.819 M = 45.0885
M = 55.05 u
So X has an atomic mass of 55.05 u ⇒ if we look at the periodic table we can find that the closest element is Manganese (Mn)
MnI2 + Cl2 → MnCl2 + I2
Answer:Molarity tells us the number of moles of solute in exactly one liter of a solution. (Note that molarity is spelled with an "r" and is represented by a capital M.) We need two pieces of information to calculate the molarity of a solute in a solution: The moles of solute present in the solution
Explanation:
Answer:
7.07
Explanation:
HA = weak acid = 0.053
A+ = conjugate base = 0.045
Ka = 7.2x10^-8
Ka = [H+][A-]/HA
7 2x10^-8 = [H+][0.045]/0.053
[H+] = 7.2x10^-8 x 0.053/0.045
= 8.48x10^-8
PH = -log[H+]
= -log[8.48x10^-8]
PH = -[login.48 + log10^-8]
PH = -0.928 - (-8)log10
= 7.07
