How much time would it take for an object to fall 4.7 meters

Physics

1 answer:

alukav5142 [94]2 years ago

4 0

Answer:

t = 0.97 s

Explanation:

Given that,

height, h = 4.7 m

We need to find the time taken by the object to fall 4.7 m.

Let it is t. Using second equation of kinematics to solve it such that,

$h=ut+\dfrac{1}{2}gt^2$

u is initial velocity, u = 0

So,

$h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}}\\\\t=\sqrt{\dfrac{2\times 4.7}{9.8}}\\\\t=0.97\ s$

So, the required time is equal to 0.97 seconds.

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