Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:
D=0.5at where d is distance, a is acceleration and t is time
D is 300 meters
a is 9.8 meter/sec squared
Solve for t in seconds
t = 61.2 seconds
v=at where v is velocity
a is 9.8 meters per second squared
t is 61.2 seconds
solve for v
v = 600 meters per second.
If it had an initial vertical velocity (v0) at the start :
d= 0.5at+v0t
and
v=at+v0
Answer:
V = 2.05× 10⁸ m/s
Explanation:
We are given;
The angle of the incidence; i = 40°
Angle of refraction; (r) = 26°
For us to find the speed of light in the material, we'll use Snell's law
From shell's law, we know that;
n = sin i/sin r = speed of light in air/Speed of light in the medium
Now, speed of light in air = 3 × 10⁸ m/s
Lets speed of light in medium be V
Thus, plugging in the relevant values to obtain;
Sin 40°/sin 26° = 3×10⁸/V
Let's make V the subject;
V = 3 × 10⁸× sin 26°/sin 40°
V = 2.05× 10⁸ m/s
For this problem, you should be able to differentiate the variables presented from each other in order to substitute them in their corresponding places in the formula or formulas to be utilized in this problem. As for this problem, the only formula to be utilized would be the formula for power which is force multiplied to distance over time or simply have force multiplied to speed since speed is equal to distance over time.
The formula would like this:
Power = force x distance / time Power = force x speed
P = 490 N x 2 m / 10 s P = 490 N x (2 m / 10 s)
P = 980 N m / 10 s P = 490 N x 0.2 m / s
P = 98 W P = 98 W
So the average power required to lift a 490-newton object a vertical distance of 2.0 meters in 10 seconds would be 98 watts.
<span>Es para la comodidad del cliente. <span>Si el satélite no estaba parado
en el cielo, entonces el cliente tendría que seguir moviendo su plato
para seguir el satélite.</span></span>
