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3 years ago

What new details are you able to see on the slide when the magnification is increased to 10x that you could not see at 4x

Physics

1 answer:

Ulleksa [173]3 years ago

4 0

Answer: A more detailed information like the nucleus of cells on the slide is seen as the magnification Increases.

Explanation:

The microscope is an instrument used in a laboratory to view magnified image of an object ( cells on a slide). There are two types:

--> Simple microscope and

--> Compound microscope.

Simple microscope is used to view an object using JUST ONE convex lens, and the image formed is usually erect and magnified.

Compound microscope has a higher magnification compared to a simple microscope. It is produced by using TWO CONVERGING LENS of short focal length. Here, the two lenses used are classified according to their positions. The lens near the object is called the objective lens while the one nearer to the eye is called the eyepiece lens.

The objective lens of the compound lens used in the laboratory has ×4, ×10, ×40, ×100 magnifications. As the magnification of the objective lens is increased from ×4 to ×10 a more detailed information of the image is seen as the diameter of field of view decreases. For example the constituents of a cell like the nucleus can be viewed using a higher magnification.

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A projectile is launched

Flauer [41]

The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

initial horizontal velocity, vₓ = 16 m/s
initial vertical velocity, $v_y =0$
time interval 1 seconds

The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

$v_y = v_0_y -gt\\\\v_y = 0 - (1\times 9.8)\\\\v_y = -9.8 \ m/s$

The horizontal component of the velocity is constant since it is not affected by gravity.

The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

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3 years ago

Find the magnitude of the force at point x = 15cm if k=10500 N/m when the work done by this force is WD= 1/2k x2

Ann [662]

Answer:

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Explanation:

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6 0

3 years ago

Review. A light spring of force constant 3.85 N/m is compressed by 8.00 cm and held between a 0.250-kg block on the left and a 0

photoshop1234 [79]

The answer is 0.245N.

<h3>What is kinetic energy?</h3>

A particle or an item that is in motion has a sort of energy called kinetic energy. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force.
Kinetic energy comes in five forms: radiant, thermal, acoustic, electrical, and mechanical.
The energy of a body in motion, or kinetic energy (KE), is essentially the energy of all moving objects. Along with potential energy, which is the stored energy present in objects at rest, it is one of the two primary types of energy.
Explain that a moving object's mass and speed are two factors that impact the amount of kinetic energy it will possess.

(b) 0.100

For the block on the left, $f_{k} =u_{k} n= 0.100(2.45N)=0.245N.$

∑ $F_{x}$ = $ma_{x}$

–0.308N+0.245N=(0.250kg)a

a=−0.252 $m/s^{2}$ if the force of static friction is not too large.

For the block on the right, $f_{k}$ = $u_{k} n$ =0.490N. The maximum force of static friction would be larger, so no motion would begin, and the acceleration is zero

To learn more about kinetic energy, refer to:

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2 years ago

A sample of gas at 23°C is placed in an expandable container with a volume of 23 mL. The gas is heated and expands to a volume o

myrzilka [38]

Based on the options given, the most likely answer to this query is B) The temperature must be converted to Kelvin. Meaning, the temperature should be in SI unit.

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3 years ago

Suppose you drive an average of 25 miles a day, for a total of 60 years in a lifetime. The total distance you would have covered

Ahat [919]

The total distance you would have covered is equivalent to going around the earth 22 times.

<h3>Total distance traveled</h3>

The total distance traveled at a given speed and time of motion is calculated as follows;

Distance = speed x time

$Distance = \frac{25 \ miles}{day} \times \frac{365 \ days}{1 \ year} \times 60 \ years\\\\Distance = 547, 500 \ miles$

<h3>Distance round the Earth</h3>

The distance round the earth or circumference of the earth of the earth has been given as 25,000 miles

<h3>Number of times round the earth</h3>

$n = \frac{547,500}{25,000} \\\\ n = 21.9 \ times \ \approx 22 \ times$

Thus, the total distance you would have covered is equivalent to going around the earth 22 times.

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2 years ago