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3 years ago

How does heart failure affect the lungs?

Chemistry

1 answer:

forsale [732]3 years ago

5 0

Answer:

Pulmonary oedema can be caused by lung disease, but when heart failure is more serious, the pressure of blood in the lungs builds-up, pushing fluid into the air sacs. This is how heart failure can lead to respiratory failure. People with pulmonary oedema will feel breathless, weak and unwell.

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What does applied chemistry have to do with making ice cream?

Lapatulllka [165]

Well you have to mix chemicals which caused a chemical reaction. When you mix salt and ice the freezing point of liquid changes. the ice gets colder

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3 years ago

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PLEASEEEEEE answer these 2 questions!! I WILL GIVE BRAINLIEST AND POINTS

Olegator [25]

Answer: B then D

Explanation:

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3 years ago

When we write the formula for an ionic compound, we are merely indicate the "molecules" in the compound with that formula. expla

belka [17]

When writing an ionic compound formula, a "molecular" form is used. The formula is made with allowance for ion charges.
For example,
Ca²⁺ and NO₃⁻ ⇒ Ca(NO₃)₂
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4 years ago

When a plant is entering the Calvin cycle of photosynthesis_____.

Andrei [34K]

B). light energy is not required to proceed

Explanation:

In the Calvin cycle of photosynthesis, light energy is not required. The Calvin cycle is light independent and it is made up of a series of redox reactions.

During photosynthesis reactions, green plants manufacture their food using carbon dioxide, sunlight and water.
During the Calvin cycle aspect, light energy is not required for chemical reactions to take place. The light energy helps to move electrons.
The cycle is also known as dark reactions.
It is at this stage that carbon dioxide combines with water to form glucose.
The reaction is initiated with light energy which produces NADPH and ATP.
The Calvin cycle follows by using the NADPH and ATP to produce glucose in the dark phase.

Learn more:

ATP brainly.com/question/2953868

Light dependent reactions brainly.com/question/6866300

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3 years ago

7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m

Anna [14]

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ $(n_{A}) = 1$

Mole ratio of the base, NaOH $(n_{B}) = 2$

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH $(M_{B}) = 0.505 M$

Volume of the acid, H₂SO₄ $(V_{A}) = 40 mL$

Molarity of the acid, H₂SO₄ $(M_{A}) = 0.505 M$

<h3>Volume of the base, NaOH $(V_{B})$ =? </h3>

$\frac{M_{A} * V_{A}}{M_{B} * V_{B}} = \frac{n_{A}}{n_{B}}\\\\\frac{0.505 * 40}{0.505 *V_{B}} = \frac{1}{2}\\\\\frac{20.2}{0.505 *V_{B}} = \frac{1}{2}$

Cross multiply

$0.505 * V_{B} = 20.2 * 2\\0.505 * V_{B} = 40.4$

Divide both side by 0.505

$V_{B} = \frac{40.4}{0.505}\\\\V_{B} = 80 mL$

Finally, we shall convert 80 mL to dm³. This can be obtained as follow:

$1000 mL = 1 dm^{3}\\\\Therefore,\\\\80 mL = \frac{80 mL * 1dm^{3}}{1000 mL}\\\\80 mL = 0.08dm^{3}$

Therefore, the volume of NaOH required is 0.08 dm³

Learn more: brainly.com/question/19053582

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3 years ago