Every particle of mass is attracted to every other particle of mass. The magnitude of the force between two objects is proportional to the product of their masses, and inversely proportional to the square of the distance between them. The direction of the force is along the line between their centers.
(NOTE: Newton's 3rd law of motion tells us that gravitational forces always come in pairs. Between two objects, there are two forces ... one in each direction. Their strengths are equal ... Your weight on Earth is exactly equal to the Earth's weight on YOU.)
Answer:2538.43 N
Explanation:
Given
Mass of Log=205 kg
Ramp angle
Coefficient of Friction=0.855
log acceleration
Let T be the Tension
Here
T=849.04+132.63+1556.76=2538.435 N
Velocity is built from speed and direction. Speeding up, slowing down, and changing direction are all the possible forms of acceleration. They're all caused by unbalanced external forces.
Answer:
Explanation:
The expression which represent the first diffraction minima by a circular aperture is given by --------eqn 1
The angle through which the first minima is diffracted is given by ---------eqn 2
As is very small so we can write
So from eqn 1 and eqn 2 we can write
--------eqn 3
Here is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture
It is given that diameter of circular aperture is 14.7 cm so
Now putting all these value in eqn 3
Answer:
30.63 m
Explanation:
From the question given above, the following data were obtained:
Total time (T) spent by the ball in air = 5 s
Maximum height (h) =.?
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Total time (T) spent by the ball in air = 5 s
Time (t) taken to reach the maximum height =.?
T = 2t
5 = 2t
Divide both side by 2
t = 5/2
t = 2.5 s
Thus, the time (t) taken to reach the maximum height is 2.5 s
Finally, we shall determine the maximum height reached by the ball as follow:
Time (t) taken to reach the maximum height = 2.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
h = ½gt²
h = ½ × 9.8 × 2.5²
h = 4.9 × 6.25
h = 30.625 ≈ 30.63 m
Therefore, the maximum height reached by the cannon ball is 30.63 m