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damaskus [11]
3 years ago
6

A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atm. If the balloon

is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atm. What is the new volume of the balloon?
5.0 L
0.19 L
4.9 L
1.9 L
Physics
1 answer:
stira [4]3 years ago
8 0

Answer:

4.9L hope this helped!

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The acceleration of a falling rock that was initially moving 5 m/s, and had a final velocity of 11 m/s after accelerating for 3
yanalaym [24]

Answer:

2 m/s²

Explanation:

Given:

v₀ = 5 m/s

v = 11 m/s

t = 3 s

Find: a

v = at + v₀

11 m/s = a (3 s) + 5 m/s

a = 2 m/s²

3 0
3 years ago
Write the equation for speed
zzz [600]

Answer:

Distance / Time = Speed

Explanation:

This is because you want to see how much distance you cover within a time interval.

For example, MPH, is a unit for speed, which is miles (distance) per hour (time)

7 0
3 years ago
How much work do you need to do if you use a force of 3 Newtons to move a table 25 meters?
Harlamova29_29 [7]

The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).

<h3>How to calculate work done?</h3>

Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.

Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.

Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:

Work done = Force (N) × distance (m)

According to this question, a force of 3 Newtons is used to move a table over a distance of 25 meters. The work done on the table can be calculated as follows;

W = 3N × 25metres

W = 75Nm

Therefore, 75Nm is the work done on the table.

Learn more about work done at: brainly.com/question/2117638

#SPJ1

6 0
1 year ago
When you lift an object by moving only your forearm, the main lifting muscle in your arm is the biceps. Suppose the mass of a fo
Sladkaya [172]

Answer:

The answers to the questions are;

The force the biceps must exert to hold a 850 g ball at the end of the forearm at distance dball = 34.0 cm from the elbow, with the forearm parallel to the floor is 166.77 N Upwards.

The force the elbow must  exert is 145.6785 N downwards.

Explanation:

We are required to analyze the system using the principle of moments as follows.

Mass of forearm = 1.30 kg

Weight of forearm = mass × acceleration due to gravity = 1.30 kg × 9.81  m/s²= 12.753 N

Location of point of action of weight of forearm = midpoint  17 cm

Forearm to biceps distance = 3.00 cm from the elbow.

Mass of the ball = 850 g

Weight of ball = mass × acceleration due  to gravity = 0.850 kg × 9.81 = 8.3385 N

Position of the ball = end of the forearm

Therefore, taking moment about the elbow, we have

∑Mₓ = 0, we take clockwise moment to be positive, therefore

8.3385 N× 34.0 cm + 12.753 N× 17 cm - F_{biceps}×3.00 cm = 0

Therefore F_{biceps}×3.00 cm = 500.31 N cm

Therefore F_{biceps} = (500.31 N·cm)/(3.00 cm) = 166.77 N Upwards

The force exerted by the elbow is given by,

Taking moment about the point of contact between the biceps and the forearm, we get

F_{elbow} × 3.00 cm = 8.3385 N× 31.0 cm + 12.753 N× 14 cm

F_{elbow} = 145.6785 N downwards.

4 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
maxonik [38]

I would say that diagram 3 is the resultant, diagram number 1 is leaning more towards the left and cannot help us much in this scenario, diagram 2 is only going left and right but not up or down so its also a false answer, diagram 4 is almost correct because it shows the A+B=R formula, but only shows figure A and not figure B.

7 0
3 years ago
Read 2 more answers
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