a)., b)., and c). are completely false.
There isn't a grain of truth among them.

In Physics, the technical definition of 'Work' is (force) times (distance).

7 0

3 years ago

A race car accelerates from 0 m/s to 30.0 m/s with a displacement of

worty [1.4K]

Answer:

4. 10.0 m/s²

Explanation:

I) if initial velocity is 'v₀', the final velocity is 'v', the accelaration is 'a', the distance is 'L' and elapsed time if 't', then:

$1. \ a=\frac{v-v_0}{t};$

$2. \ L=\frac{at^2}{2}.$

II) using these two equations after substitution v₀=0; v=30 and L=45:

$\left \{{{45 =\frac{at^2}{2}} \atop {a=\frac{30-0}{t} }} \right.$

$\left \{ {{at^2=90} \atop {at=30}} \right. \ \ \left \{ {{a=10} \atop {t=3}} \right.$ $=> \ a=10\frac{m}{s^2}$

6 0

3 years ago

Which term is defined as a change in an object's position relative to a reference point?

Gre4nikov [31]

The answer would be REFERENCE POINT

4 0

3 years ago

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What is the weight of a dog with a mass of 12 kg? Explain how you obtained your answer.

butalik [34]

Answer: 117.60N

Explanation:

Weight is a force. Therefore, we can use the force formula to find weight.

$Formula: W=m*g$

W = weight

m = mass

g = acceleration due to gravity ( $9.8m/s^2$ )

$W=(12kg)(9.8m/s^2)\\W=117.60N$

5 0

3 years ago

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