In
this case, we can simply use a ruler to measure the heights of the signal. Use the
same ruler all throughout to reduce deviations in the measurement.
So
for example we have 3 isotopes, so we get 3 signals with heights of (for
example):
isotope
1 = 62
isotope
2 = 2
isotope
3 = 8
Therefore
the mass of the signals would be:
62
+ 2 + 8 = 72
The
fractional abundance of each isotope would be:
frac
isotope 1 = 62/72 = 0.86
frac
isotope 2 = 2/72 = 0.03
<span>frac
isotope 3 = 8/72 = 0.11</span>
The Kj of heat that are needed to completely vaporize 1.30 moles of H2O if the heat of vaporization for water is 40.6 Kj/mole is calculated as below
Q(heat) = moles x heat of vaporization)
=1.30 mol x40.6 kj/mol= 52.78 Kj is needed
The answer is leucine would be in the interior, and serine would be on the exterior of the globular protein.
The side chain (R group) of the amino acid serine is CH₂OH. The side chain of the amino acid leucine is CH₂CH(CH₃)₂. In globular protein, leucine found in the interior, and serine found on the exterior. The nature of side chain decides the amino acid position in the globular protein , as CH₂CH(CH₃)₂ this is hydrophobic and CH₂OH is hydrophlic.