In chemistry, the molar mass M is a physical property defined as the mass of a given substance (chemical element or chemical compound) divided by its amount of substance. The base SI unit for molar mass is kg/mol. However, for historical reasons, molar masses are almost always expressed in g/mol.
Hope this helped!
Good luck :p
~Emmy <3
Answer:
To interpret a 13C-NMR spectrum we will use some standards very simple. A 13C-NMR spectrum gives us the following information:
1. Indicates the number of non-equivalent carbons in the molecule.
2. Measuring the chemical shift we can intuit the environment
electronic and determine the next functional groups.
3. In this case we cannot count on integration since the different
carbons have different relaxation times.
The number of peaks in the spectrum indicates the number of types of carbon present in the analyzed substance.
The factors that influence the chemical shift of the signals in the 13C NMR are:
- electronegativity of carbon bound groups
-
carbon hybridization
Explanation:
The nuclear magnetic resonance of C13 is complementary to that of H1. This technique is used to determine the magnetic environment of carbon atoms.
Answer: Warm ocean air then rises into the storm, then forming an area of low pressure underneath. :)
Explanation:
What kind of question is this
Answer:
Explanation:
Hello, in this case, the lead is catching heat and the water losing it, that's why the heat relation ship is (D is for Δ):
![DH_{lead}=-DH_{water}](https://tex.z-dn.net/?f=DH_%7Blead%7D%3D-DH_%7Bwater%7D)
Now, by stating the heat capacity definition:
![m_{Pb}C_{Pb}*(T_{eq}-T_{lead}=-m_{H_2O}C_{H_2O}*(T_{eq}-T_{H_2O})\\](https://tex.z-dn.net/?f=m_%7BPb%7DC_%7BPb%7D%2A%28T_%7Beq%7D-T_%7Blead%7D%3D-m_%7BH_2O%7DC_%7BH_2O%7D%2A%28T_%7Beq%7D-T_%7BH_2O%7D%29%5C%5C)
Solving for the equilibrium temperature:
![T_{eq}=\frac{m_{Pb}C_{Pb}T_{Pb}+m_{H_2O}C_{H_2O}T_{H_2O}}{m_{Pb}C_{Pb}+m_{H_2O}C_{H_2O}} \\\\T_{eq}=\frac{2.04g*0.128J/(g^oC)*10.8^oC+7.74g*4.18J/(g^oC)*52.2^oC}{2.04g*0.128J/(g^oC)+7.74g*4.18J/(g^oC)} \\\\T_{eq}=51.87^oC](https://tex.z-dn.net/?f=T_%7Beq%7D%3D%5Cfrac%7Bm_%7BPb%7DC_%7BPb%7DT_%7BPb%7D%2Bm_%7BH_2O%7DC_%7BH_2O%7DT_%7BH_2O%7D%7D%7Bm_%7BPb%7DC_%7BPb%7D%2Bm_%7BH_2O%7DC_%7BH_2O%7D%7D%20%5C%5C%5C%5CT_%7Beq%7D%3D%5Cfrac%7B2.04g%2A0.128J%2F%28g%5EoC%29%2A10.8%5EoC%2B7.74g%2A4.18J%2F%28g%5EoC%29%2A52.2%5EoC%7D%7B2.04g%2A0.128J%2F%28g%5EoC%29%2B7.74g%2A4.18J%2F%28g%5EoC%29%7D%20%5C%5C%5C%5CT_%7Beq%7D%3D51.87%5EoC)
Which is very close to the water's temperature since the lead's both mass and head capacity are lower than those for water.
Best regards.