The number of molecules that are in balloon are = 2.227 x10^23 molecules
<h3> calculation</h3>
calculate the number of moles of NO
moles = mass/molar mass
molar mass of NO = 14+ 16 = 30 g/mol
moles is therefore= 11.1 g/30g/mol= 0.37 moles
by use of Avogadro's constant that is
1 mole= 6.02 x10^23 molecules
0.37 =? molecules
=(6.02 x10^23 x 0.37 moles)/ 1mole=2.227 x10^23 molecules
As per the question, the mass of the nitrogen gas m = 22.25 gram.
The latent heat of vaporization of nitrogen = 199.0 j/g
As per the question, the nitrogen gas will condense. During condensation, the nitrogen gas will lose or release heat equal to its latent heat.
Hence, the heat released by nitrogen gas Q = ml = 22.25 × 199.0 J = 4427.75 J.
Hence, the amount of heat released will be 4427.75 J.
<h3>How can you figure out how much heat is in each gram?</h3>
The formula: can be utilized to determine energy. Q = mc ∆T. In the equation, Q stands for energy expressed in joules or calories, m for mass expressed in grams, c for specific heat, and T for temperature change, which is the difference between the final temperature and the initial temperature. Water has a specific heat of 1 calorie/gram °C.
Learn more about energy here:
brainly.com/question/1932868
#SPJ4
One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
