We assume that the rod's weight is evenly distributed, making its center of gravity 0.675 m from the end.
First, we calculate the moment present on the rod:
τ = F*d
τ = m*g*d
τ = 0.25 * 9.81 * 0.675
τ = 1.66
Next, in the case of rotational motion, Newton's second law is:
τ = Iα, where I is moment of inertia and α is the angular acceleration
The moment of inertia for a rod is:
I = (ML²)/12
I = (0.25*1.35²)/12
I = 0.038
Now, we use the formula given by Newton's law:
α = τ / I
α = 1.66 / 0.038
α = 43.7 rad/s²
The angular acceleration is 43.7 radians per seconds squared.
Answer:
Question: What is the current in a 160V circuit if the resistance is 2Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 2Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 2
⇒ I = 160 / 2 = 80A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 20Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 20Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 20
⇒ I = 160 / 20 = 8A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 10Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 10Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 10
⇒ I = 160 / 10 = 16A
\rule{200}2
Question: Based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? Increases?
Answer:
From ohms law
⇒ I = V / R
If we take Voltage as proportionality constant
⇒ I ∝ 1 / R
So, we can conclude that current is inversely proportional to resistance.
From 2, 3, 4 questions we can conclude that,
If resistance increases, current decreases and when resistance decreases, current increases.
\rule{200}2
Question: What voltage is required to move 6A through 5Ω?
Answer:
Resistance ( R ) = 5Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 5
⇒ V = 30V
\rule{200}2
Question: What voltage is required to move 6A through 10Ω?
Answer:
Resistance ( R ) = 10Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 10
⇒ V = 60V
\rule{200}2
Question:What voltage is required to move 6A through 20Ω?
Answer:
Resistance ( R ) = 20Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 20
⇒ V = 120V
\rule{200}2
Um this doesn't make since to me since you did not clearly state your awnser
Answer:using Newton third law
Let initial velocity of block be u1=3m/s
Mass of moving block m1 =1kg
Final velocity of block =V
Mass of stationary block m2= 4kg
Since they stick together, their final velocity will be the same.
m1u1 + m2u2=(m1+m2)v
(1*3)+(0*4)=(1+4)v
3=5v
Divide both sides by 5
V=0.6
Final velocity is 0.6m/s
Explanation:
That's false. Both moons of Mars are tiny, and Mercury and Venus have no moons at all.