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3 years ago

Consider this reaction at equilibrium:

Chemistry

1 answer:

Gnom [1K]3 years ago

3 0

Answer:

a. NO is added to the reaction mixture ⇒ to the left

b. BrNO is added to the reaction mixture ⇒ to the right

c. Br₂ is removed from the reaction mixture ⇒ to the right

d. Pressure is increased ⇒ to the left

Explanation:

The reaction at equilibrium is the following:

2BrNO (g) → 2NO (g)+ Br₂ (g)

The left side is the reactants side (2 BrNO) and the right side is the products side (2 NO + Br₂).

a. NO is added to the reaction mixture

NO is a product, in the right side of the equation. If a product is added, the equilibrium will shift to the opposite side, to the left, to form more reactants and compensate for the addition.

b. BrNO is added to the reaction mixture

BrNO is a reactant, in the left side of the equation. If a reactant is added to a reaction at equilibrium, more product will be formed in compensation. Therefore, the equilibrium will shift to the right.

c. Br₂ is removed from the reaction mixture

Br₂ is a product, in the right side. If it is removed, the system will compensate for the remotion by forming more product, so the reaction will shift to the right.

d. Pressure is increased

Since both reactants and products are in the gas phase, the equilibrium is affected by pressure. If pressure is increased, the equilibrium will shift to the side of the reaction with the fewest number of moles. The reactants side (left) has 2 moles of BrNO while the products side (right) has 3 moles (1 mol NO + 1 mol Br₂ = 3 moles of gas). Therefore, the reactants side has the fewest number of moles, so the equilibrium will shift to the left.

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1. In the investigation of an unknown alcohol, there was a positive Jones test and a negative Lucas test. What deductions may be

pogonyaev

Answer:

1. When observing a positive test for the jones reagent and negative for the Lucas test, it indicates that it is in the presence of a primary alcohol.

Jones reagent behaves like a strong oxidant, where it transforms the primary alcohols into carboxylic acids and the secondary alcohols into ketones. Tertiary alcohols do not react.

With the Lucas test, tertiary alcohols react immediately producing turbidity, while secondary alcohols do so in five minutes. Primary alcohols do not react significantly with Lucas reagent at room temperature.

2. No reaction (See the attached drawing)

3. (see the attached drawing)

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4 years ago

What is 5 divided by 2.7

Strike441 [17]

5 divided by 2.7 is 0.54

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3 years ago

The partial pressure of O2 in air at sea level is 0.21atm. The solubility of O2 in water at 20∘C, with 1 atm O2 pressure is 1.38

adell [148]

Answer:

$1.21x10^{-3}$ M

Explanation:

Henry's law relational the partial pressure and the concentration of a gas, which is its solubility. So, at the sea level, the total pressure of the air is 1 atm, and the partial pressure of O2 is 0.21 atm. So 21% of the air is O2.

Partial pressure = Henry's constant x molar concentration

0.21 = Hx1.38x $10^{-3}$

H = $\frac{0.21}{1.38x10^{-3} }$

H = 152.17 atm/M

For a pressure of 665 torr, knowing that 1 atm = 760 torr, so 665 tor = 0.875 atm, the ar concentration is the same, so 21% is O2, and the partial pressure of O2 must be:

P = 0.21*0.875 = 0.1837 atm

Then, the molar concentration [O2], will be:

P = Hx[O2]

0.1837 = 152.17x[O2]

[O2] = 0.1837/15.17

[O2] = $1.21x10^{-3}$ M

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My answer would be a. True

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Read 2 more answers

Why do some atoms form positive ions and others form negative ions?

Scrat [10]

It is energetically favorable for all atoms to have a complete outer electron shell. Loosely, the atoms on the left hand side of the periodic table only have a few extra electrons in their outer shell so it is energetically favorable for them to lose them. The atoms on the right hand side of the periodic table almost have enough electrons in their outer shell and so they have a tendency to gain them. Once electrons have left an electron shell, an atom will have a positive charge because it has more protons (positive charges) than electrons (negative charges). Similarly, an electron which has gained electrons to complete its outer shell will have a negative charge because it now has more electrons (negative charge) than protons (positive charge).

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