Answer:
The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:
CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)
Explanation:
Cobalt (ii) hydroxide is an inorganic compound consisting of cobalt (ii) ions, Co²+ and hydroxide ions, OH-. It is insoluble in water and the pure form known as the beta form is a pink-coloured solid. The impure form which incorporates other anions in its molecular structure is blue in colour and is ustable.
Cobalt (ii) hydroxide is formed as precipitate when an alkaline metallic hydroxide such as sodium hydroxide is mixed with an aqueous cobalt (ii) salt such as cobalt (ii) sulfate. The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:
CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)
Being a basic hydroxide, cobalt (ii) hydroxide neutralizes acids to form cobalt (ii) salts and water. For example: Co(OH)₂ (s) + H₂SO₄ (aq) ---> CoSO₄ (aq) + H₂O
Thus, cobalt (ii) hydroxide is soluble in acids.
Cobalt(II) hydroxide is used mostly as a drying agent for paints, varnishes, and inks. It is also useful in the preparation of other cobalt compounds.
Answer:
I believe the answer is C. difficile but to be honest I don't know for sure
Answer:
And that means fish must be able to survive down here. This is due to a special property of water: the elasticity of H2O. We know that when the temperature sinks below freezing, water first contracts and then expands as it begins to turn to ice. Ice, being lighter than water, floats.
Explanation:
The property of water that allows fish to survive in a lake that is frozen over is the fact that ice is less dense than liquid water.
The answer is an acid.
That is a substance that gives up a proton during a chemical reaction, raising the hydrogen ion concentration of water, is most appropriately called an acid.
Acid is a substance that gives protons in its aqueous solution, and that the hydrogen ion concentration of that aqueous solution .
Answer:
Explanation:
In a simple cubic lattice lattice, the atoms are present at the eight corners of the cibe.
Since it is mentioned that the fluorine is present at the corners and also 1 corners are shared by 8 unit cells. So, share of atom in one unit cell is:-
Also, the metal, M occupy half of the body centre. A cube has only one body centre. So, share of M in each unit cell:-
Thus, the formula is:-
Or simplifying