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Zolol [24]
3 years ago
5

If you have 6 Hydrogen atoms on the Reactant side of the equation how many do need on the Product side? Explain.

Chemistry
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

Explanation:

???

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Ways to manage non-biodegradable waste​
Lisa [10]

Answer:

The following are some ways of safely disposing of non-biodegradable waste.

1. Take them to a local recycling facility. Separate metal, plastic, glass, and other non-biodegradable waste and store them ready for recycling.

2. Combustion and energy recovery.

3. Disposal at sanitary facilities.

4. Reduce.

5. Landfills.

Explanation: Hope it helps! ^_^"

(G00gle)

7 0
3 years ago
CS2 (s) + 3 O2 (g) → CO2 (g) + 2 SO2 (g)
Natasha_Volkova [10]

Answer:

2.067 L ≅ 2.07 L.

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g),</em>

It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.

  • At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:

It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.

<u><em>using cross multiplication:</em></u>

1.0 mol of O₂ represents → 22.4 L.

??? mol of O₂ represents → 3.1 L.

∴ 3.1 L of O₂ represents = (1.0 mol)(3.1 L)/(22.4 L) = 0.1384 mol.

  • To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:

<u><em>Using cross multiplication:</em></u>

3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.

0.1384 mol of O₂ produce → ??? mol of SO₂.

∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.

  • Again, using cross multiplication:

1.0 mol of SO₂ represents → 22.4 L, at STP.

0.09227 mol of SO₂ represents → ??? L.

∴ The no. of liters of SO₂ will be produced = (0.09227 mol)(22.4 L)/(1.0 mol) = 2.067 L ≅ 2.07 L.

8 0
3 years ago
This is a graded Quiz and I need all of the answers to be right but I am not sure so I need help this is a 3.08 science Quiz and
Setler79 [48]

Answer:

1 true

Explanation:

bcz it is true

8 0
3 years ago
If all materials were good conductors of heat, would people and animals be able to live in cold climates? Explain your answer.
miss Akunina [59]
Yes we would be able to live in cold climates.
6 0
3 years ago
How many molecules of water are produced by the combustion of 3.00 g of methane
Karo-lina-s [1.5K]
3/8 NA = 3/8 x 6.023 x 10^23 molecules of h2o
so, we can easily conclude that 1mole of CH4 gives 2mole of H2o
5 0
3 years ago
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