Answer:
Thrust developed = 212.3373 kN
Explanation:
Assuming the ship is stationary
<u>Determine the Thrust developed</u>
power supplied to the propeller ( Punit ) = 1900 KW
Duct distance ( diameter ; D ) = 2.6 m
first step : <em>calculate the area of the duct </em>
A = π/4 * D^2
= π/4 * ( 2.6)^2 = 5.3092 m^2
<em>next : calculate the velocity of propeller</em>
Punit = (A*v*β ) / 2 * V^2 ( assuming β = 999 kg/m^3 ) also given V1 = 0
∴V^3 = Punit * 2 / A*β
= ( 1900 * 10^3 * 2 ) / ( 5.3092 * 999 )
hence V2 = 8.9480 m/s
<em>Finally determine the thrust developed </em>
F = Punit / V2
= (1900 * 10^3) / ( 8.9480)
= 212.3373 kN
Answer:
a. 8.136 × 10¹³ km b. 2.669 × 10¹⁹ feet
Explanation:
a. What is this distance in kilometers?
Since Sirius A is 8.6 light years away from Earth and one light year = distance travelled by light in a year = 3 × 10⁸ m/ s × 365 days/year × 24 hr/day × 3600 s/hr = 9.4608 × 10¹⁵ m = 9.4608 × 10¹² km.
Then 8.6 light years = 8.6 × 1 light year
= 8.6 × 9.4608 × 10¹² km
= 81.363 × 10¹² km
= 8.1363 × 10¹³ km
≅ 8.136 × 10¹³ km
b. What is this distance in feet?
Since 1 meter = 3.28 feet,
8.6 light years = 8.1363 × 10¹² km
= 8136.3 × 10¹⁵ m
= 8136.3 × 10¹⁵ × 1 m
= 8136.3 × 10¹⁵ × 3.28 feet
= 26687.1 × 10¹⁵ feet
= 2.66871 × 10¹⁹ feet
≅ 2.669 × 10¹⁹ feet
Answer:
b. Conservation of charges
Explanation:
The distance it traveled and the time that it took to travel that distance
Answer:
0.958891203 m/s²
Explanation:
N = Weight of crate = 900 N
= Coefficient of friction = 0.25
Force of friction acting on the force applied
Force used to pull the crate
The net force is
Acceleration is given by
The magnitude of the acceleration of the crate is 0.958891203 m/s²
