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3 years ago

Match the following:

Physics

1 answer:

labwork [276]3 years ago

7 0

Answer:

iron metal :chromium
machinery part :nickel or chromium
ornamentation and decoration pieces :silver and gold
processed food :tin coated iron can
bridges and automobiles :zinc metal
distilled water:bad conductor

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If the capacity of the lungs of an adult were 3.8 L, how many moles of air would the lungs contain at body temperature and atmos

Ahat [919]

Answer:

0.14955 mol

Explanation:

We can solve this problem using the ideal gas law

$P \ V = \ n \ R \ T$

where P is the pressure, V the volume, n the number of moles, R the ideal gas constant and T the temperature.

We can use the atmospheric pressure as 1 atm, and the body temperature as 36.5 °C, in Kelvin this is:

$T_{body} = 36.5 \° C = (36.5 + 273.15) K = 309.65 \ K$

The ideal gas constant is:

$R = 0.082057 \frac{L \ atm}{ K \ mol}$

taking all this in consideration, the number of moles will be:

$n = \frac{P \ V}{ R \ T }$

$n = \frac{1 \ atm * 3.8 \ L }{ 0.082057 \frac{L \ atm}{ K \ mol}$ * 309.65 \ K } [/tex]

$n = 0.14955 \ mol$

3 0

3 years ago

A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during

Alexeev081 [22]

The acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

The given parameters;

initial velocity of the engine, u = 1341 m/s
final velocity of the engine, v = 7600 m/s
time of motion, t = 2 minutes = 2 x 60 s = 120 s

The acceleration of the SRB and main engine is calculated as follows;

$a = \frac{\Delta v}{\Delta t } \\\\a = \frac{7600 - 1341}{2 \times 60 s} \\\\a = 52.16 \ m/s^2$

Thus, the acceleration of the SRB and main engine during the first 2.0 minutes of flight is 52.16 m/s².

Learn more here:brainly.com/question/17067013

4 0

3 years ago

A box weighing 10 N is 4 m away from the fulcrum. How much force must be applied 1 m away on the opposite end of the fulcrum in

julia-pushkina [17]

Answer: Socratic

Explanation: i’m not sure but you can use Socratic it’s a good app that helps

4 0

3 years ago

3. What are the forces present on the rope?

irina1246 [14]

Answer:

The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.

7 0

3 years ago

If a m = 74.7 kg m=74.7 kg person were traveling at v = 0.800 c v=0.800c , where c c is the speed of light, what would be the ra

igomit [66]

Answer:

$\frac{E}{E_c} =3.125$

Explanation:

The kinetic energy of a rigid body that travels at a speed v is given by the expression:

$E_c=\frac{1}{2} mv^2$

The equivalence between mass and energy established by the theory of relativity is given by:

$E=mc^2$

This formula states that the equivalent energy $E$ can be calculated as the mass $m$ multiplied by the speed of light $c$ squared.

Where $c$ is approximately $3\times 10^{8} m/s$

Hence:

$E_c=\frac{1}{2} (74.7)*(0.8*3\times 10^{8} )^2=2.15136\times 10^{18} J$

$E=(74.7)*(3\times 10^{8} )^2 =6.723\times 10^{18} J$

Therefore, the ratio of the person's relativistic kinetic energy to the person's classical kinetic energy is:

$\frac{E}{E_c} =\frac{6.723\times 10^{18}}{2.15136\times 10^{18}} =3.125$

4 0

3 years ago

Match the following:​

Match the following: