If the effort distance = 8 meters and the resistance distance = 1/2 meter. How much force does this man have to apply to lift th
1 answer:
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Answer:
Explanation:
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Answer:
The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp
Explanation:
<u>Polar moment of Inertia</u>
= 0.14374 in 4
<u>Maximum sustainable torque on the solid circular shaft</u>
=
= 3658.836 lb.in
= lb.ft
= 304.9 lb.ft
<u>Maximum sustainable torque on the tubular shaft</u>
=
= 3334.8 lb.in
= lb.ft
= 277.9 lb.ft
<u>Maximum sustainable power in the solid circular shaft</u>
=
= 4023.061 lb. ft/s
= hp
= 7.315 hp
<u>Maximum sustainable power in the tubular shaft</u>
=
= 3666.804 lb.ft /s
= hp
= 6.667 hp