If the effort distance = 8 meters and the resistance distance = 1/2 meter. How much force does this man have to apply to lift th
1 answer:
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Answer: 2.04 s
Explanation:
Let the initial velocity be v, Angle of projectile be
Then the horizontal component = v cos θ = 16 m/s
Vertical component of velocity = v sin θ = 20 m/s
Time taken to reach the highest point is half the time taken for total flight.
Time for total flight,
Thus, the football takes 2.04 s to rise to the highest point of its trajectory.