Before the skydiver opens the parachute, his velocity would be increasing greatly as much as 9.8 m/s². Opening the parachute would increase the surface area to which air may cause resistance. The skydiver then reaches his terminal velocity.
Answer: D) subatomic, atomic, and nanometer-size systems.
Explanation: Quantum mechanics applies to subatomic, atomic, and nanometer-size systems.
Answer:
a) 0.049 m
b) Yes, increase
Explanation:
Draw a free body diagram.
In the y direction, there are three forces acting on the feeder. Two vertical components of the tension forces in each rope pulling up, and weight force pulling down.
Apply Newton's second law to the feeder in the y direction.
∑F = ma
2Ty − mg = 0
Ty = mg/2
Let's say the distance the rope sags is d. The trees are 4m apart, so the feeder is 2m horizontally from either tree. Using Pythagorean theorem, we can find the length of the rope on either side:
L² = 2² + d²
L = √(4 + d²)
Using similar triangles, we can write a proportion using the forces and distances.
Ty / T = d / L
Substitute:
(mg/2) / T = d / √(4 + d²)
Solve for d:
Td = mg/2 √(4 + d²)
T² d² = (mg/2)² (4 + d²)
T² d² = (mg)² + (mg/2)² d²
(T² − (mg/2)²) d² = (mg)²
d² = (mg)² / (T² − (mg/2)²)
d = mg / √(T² − (mg/2)²)
Given m = 2.4 kg and T = 480 N:
d = (2.4) (9.8) / √(480² − (2.4×9.8/2)²)
d = 0.049 m
b) If a bird lands on a feeder, this will increase the tension in the rope to support the bird's weight.
<u>Ques</u><u>tion</u><u>:</u>
Azaria's pet lizard runs a distance of 45 meters in 24 seconds. What is the speed of the lizard?
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<u>Solu</u><u>tion</u><u>:</u>
We are given,
- Distance = d = 45 m
- Time = t = 24 s
Speed is given by:
Putting the given values,
s = (45 m)/(24 s)
=> s = 1.875 m/s
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Answer:
Hydroelectricity
Explanation:
There are varipus situations in which mechanical energy is turned into electrical energy for use but the most common is in hydroelectricity.
The attachment will give a better understanding pf how this works.
