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marishachu [46]
3 years ago
5

Caves are formed from?​

Physics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

Answer:

caves are mainly formed by water or in some other cases limestone.

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Straight wire of indefinite length (transient) passed by an electric current of 5.0 A. The magnetic field generated around this
olchik [2.2K]

Answer:

C. 2.0 cm

Explanation:

The magnetic field around the wire at point M is given by Biot-Savart Law:

B = \frac{\mu_o I}{2\pi R}

where,

B = Magnetic field = 50 μT = 5 x 10⁻⁵ T

I = current = 5 A

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

R = distance of point M from wire = ?

Therefore,

5\ x\ 10^{-5}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(5\ A)}{2\pi R}\\\\R = \frac{(2\ x\ 10^{-7}\ N/A^2)(5\ A)}{5\ x\ 10^{-5}\ T}\\

R = 0.02 m = 2 cm

Hence, the correct option is:

<u>C. 2.0 cm</u>

7 0
3 years ago
How long has the international space station been in orbit.
Blizzard [7]

Answer:

21 years and 97 days

Explanation:

I think

4 0
2 years ago
. While at the dentist’s office, Marion noticed the x-ray images of her teeth looked very
kkurt [141]

Answer:

B

Explanation:

7 0
3 years ago
The scientific principle which explains the observation that the amount of heat transfer accompanying a change in one direction
Sphinxa [80]

Answer:

The Law of the Conservation of Energy

Explanation:

The Energy Conservation Act tells us that any form of energy changes from one form to another. And that you can never have a higher amount of energy than you originally got. That is, if you have 100 [J] of energy to be transferred as heat from one medium to another, only 100 [J] can be used to be transferred, no amount greater than this value can be transferred.

The particular study of Energy Transfer in the form of heat is important in sciences such as thermodynamics and heat transfer.

4 0
3 years ago
Please solve this asap​
brilliants [131]

Let \vec u and \vec v be the vectors, and let x=\|\vec u\|=\|\vec v\| be their common magnitude.

The resultant \vec u + \vec v is \sqrt 2 times larger in magnitude than either vector alone, so \|\vec u+\vec v\| = \sqrt2\,x.

Recall the dot product identity

\vec a \cdot \vec b = \|\vec a\| \|\vec b\| \cos(\theta)

where \theta is the angle between the vectors \vec a and \vec b. In the special case of \vec a=\vec b, we get

\vec a \cdot \vec a = \|\vec a\|^2 \cos(0^\circ) \implies \|\vec a\| = \sqrt{\vec a\cdot\vec a}

Now, to get the angle between \vec u and \vec v, we have

\vec u \cdot \vec v = \|\vec u\| \|\vec v\| \cos(\theta) \implies \cos(\theta) = \dfrac{\vec u \cdot \vec v}{x^2}

To compute the dot product, we take the dot product of the resultant with itself.

(\vec u+\vec v) \cdot (\vec u + \vec v) = \|\vec u + \vec v\|^2

Solve for \vec u\cdot\vec v.

(\vec u\cdot\vec u) + 2(\vec u\cdot\vec v) + (\vec v\cdot\vec v) = \|\vec u + \vec v\|^2

\|\vec u\|^2 + 2(\vec u\cdot \vec v) + \|\vec v\|^2 = \|\vec u+\vec v\|^2

x^2 + 2(\vec u \cdot \vec v) + x^2 = (\sqrt2\,x)^2

2(\vec u\cdot\vec v) + 2x^2 = 2x^2

2(\vec u\cdot\vec v) = 0

\vec u\cdot\vec v = 0

Since their dot product is zero, \vec u and \vec v are perpendicular, so \theta=90^\circ.

7 0
2 years ago
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