Answer:
C Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)
Explanation:
In order to determine the correct rate law, let's use Trial 1 as baseline. Therefore:
An increase in [A] in Trial 2 by a factor of
leads to an increase in the rate of reaction by a factor of 2 (i.e. the reaction rate is doubled). Thus, there is second order in [A].
Similarly,
An increase in [B] in Trial 3 by a factor of 1.667 leads to an increase in the rate of reaction by a factor of 1.667. Thus, there is first order in [B].
Futhermore,
An increase in [C] in Trial 4 by a factor of 1.71 leads to a decrease in the rate of reaction by 1.71. Thus, there is inverse first order in [C].
Therefore, the correct rate law is:
Rate ![=k [A]^{2} [B][C]^{-1}](https://tex.z-dn.net/?f=%3Dk%20%5BA%5D%5E%7B2%7D%20%5BB%5D%5BC%5D%5E%7B-1%7D)
Answer:
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Hey there!
The pH of a weak base (in this case, pyridine is a weak base) is calculated by using the weak base equation, and then solving it.
C5H5N; Kb= 1.7 x 10⁻⁹
pH = -log [H⁺]
we can also say that pH = 14 + log [OH⁻]
Plugging into the weak base equation, we know that Kb = [OH⁻][BH⁺] / [B]
This can be solved using an ice chart, which will then simplify to :
Kb = [x][x] / [0.50-x]
We can assume that x is very small in comparison to the 0.5 , so we consider it zero.
Then plug in and solve for x. 1.79 *10-9 = x² / 0.5
x = 2.992 * 10⁻⁵
ince X is equal to the [OH⁻] concentration, we can plug it into the second pH equation, and get the pH!
pH = 14+ log 2.99 * 10⁻⁵
pH = 9.48
Hope that helps!