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horrorfan [7]
3 years ago
9

A 3-m-high large tank is initially filled with water. The tank water surface is open to the atmosphere, and a sharp-edged 10-cm-

diameter orifice at the bottom drains to the atmosphere through a horizontal 80-m-long pipe. The total irreversible head loss of the system is determined to be 1.7 m. In order to drain the tank faster, a pump is installed near the tank exit. Determine the pump head input necessary to establish an average water velocity of 6.5 m/s when the tank is full. Disregard the effect of the kinetic energy correction factors.
Physics
1 answer:
DanielleElmas [232]3 years ago
5 0
3-m-high large tank is initially filled with water. The tank water surface is open to the atmosphere, and a sharp-edged 10-cm-diameter orifice at the bottom drains to the atmosphere through a horizontal 80-m-long pipe. If the total irreversible head loss of the system is determined to be 1.5 m, determine the initial velocity of the water from the tank. Disregard the effect of the kinetic energy correction factors.
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A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When th
aev [14]

Answer:

x_2=1.60m

Explanation:

From the Question We are told that

Initial Force F_1=5800N

Final Force F_2=6500N

Distance between the front and rear wheels \triangle x=3.20 m

Since

 \triangle x=3.20 m

Therefore

 x_1+x_2=3.20

 x_1=3.20-x_2

Generally the equation for The center of mass is at x_2 is mathematically

given by

 x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}

 x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}

 2*F_1*x_2 =3.20F_1

 x_2=1.60m

6 0
3 years ago
a car takes 125 ft to brake from 60 to 0 mph. Assume that the acceleration of the Prius is constant while braking. Find how long
max2010maxim [7]

Answer:

2.84 seconds

Explanation:

t = ?

distance = 125

Velocity origianal = 60 m/hr = 88 ft/s

     AVERAGE velocity = 88/2 = 44 ft/s

44 t = 125

t = 125/44 = 2.84 s

7 0
2 years ago
A certain capacitor, in series with a resistor, is being charged. At the end of 10 ms its charge is half the final value. The ti
vichka [17]

To solve this problem we will apply the expression of charge per unit of time in a capacitor with a given resistance. Mathematically said expression is given as

q(t) = e^{-\frac{t}{(R*C)}}

Here,

q = Charge

t = Time

R = Resistance

C = Capacitance

When the charge reach its half value it has passed 10ms, then the equation is,

\frac{1}{2}*q_{final} = e^{-\frac{0.01}{(R*C)}}

Ln(\frac{1}{2}) = -\frac{0.01}{RC}

- RC = \frac{0.01}{Ln(1/2)}

RC = 0.014s

We know that RC is equal to the time constant, then

T = RC  = 0.014s = 14ms

Therefore the time constant for the process is about 14ms

5 0
3 years ago
I will give u BRAINILIEST and 15 points
o-na [289]
The answer is D interferometry
3 0
3 years ago
Read 2 more answers
How many kWh of energy does a 550-W toaster use in the morning if it is in operation for a total of 5.0 min? At a cost of 9.0 ce
iren [92.7K]

Answer:

0.0458 kWh

6.5736 cents

Explanation:

The formula for electric energy is given as

E = Pt................. Equation 1

Where E = Electric energy, P = Electric power, t = time.

Given; P = 550 W, t = 5 min = (5/60) h = 0.083 h.

Substituting into equation 1

E = 550(0.083)

E = 45.83 Wh

E = (45.83/1000) kWh

E = 0.0458 kWh.

Hence the kWh = 0.0458 kWh.

If the makes a toast four morning per week, and the are Four weeks in a month.

Total number days he makes toast in a month = 4×4 = 16 days.

t = 16×0.083 h = 1.328 h.

Total energy used in a month = 550(1.328)

E = 730.4 Wh

E = 0.7304 kWh.

If the cost of energy is 9.0 cents per kWh,

Then for 0.7304 kWh  the cost will be 9.0(0.7304) = 6.5736 cents.

Hence this would add 6.5736 cents to his monthly electric bill

3 0
3 years ago
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