Cell are small and us human can't see them with our own eyes. it is in possible to see cell without a microscope
If 1 ken is 1.97 meter, then 1 square ken is 3.8809 square meters, and one cubic ken is 7.645373. As for the cylindrical tank, the volume of it would be 10.835 times the radius of the cylinder time 1.97^2 times pi. As you didn't specify the radius, I can't give the exact answer but that would be how to get it.
Newton's three forces, normal, tension and friction, are present in a surprising number of physical situations
Newton's Laws, that describe the relationship between an obejct and the forces acting upon it, apply in almost every physical situation, from quantum mechanics to electricity.
The correct answer is:
Newton’s laws can explain the forces that occur between objects every day
Answer:
(A) 88.92 cm
(B) 22.22 cm
Explanation:
distance (s) = 200 cm = 0.2 m
initial velocity (v) = 0 m/s
acceleration due to gravity (g) = 9.8 m/s^{2}
lets first find the time (T) it takes for the first drop to strike the floor
from s = ut + 
200 = 0 + 
200 = 
200 / 4.9 = 
T = 6.4
(A) When the first drop strikes the floor, how far below the nozzle is the second drop.
we can find how far the second drop was when the first drop hits the ground from the formula s = ut + 
where
- s = distance
- u = initial velocity = 0
- t = time, since the drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall there wold be 3 time intervals and this can be seen illustrated in the attached diagram. therefore the time of the second drop = 2/3 of the time it takes the first drop to strike the ground (
) - a = acceleration due to gravity = 9.8 m/s^{2}
substituting all required values we have
s = 0 + (
)
s = 0 + (
)
s = 88.92 cm
(B) When the first drop strikes the floor, how far below the nozzle is the third drop.
we can find how far the third drop was when the first drop hits the ground from the formula s = ut + 
where
- s = distance
- u = initial velocity = 0
- t = time, since the drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall there wold be 3 time intervals and this can be seen illustrated in the attached diagram. therefore the time of the third drop = 1/3 of the time it takes the first drop to strike the ground (
) - a = acceleration due to gravity = 9.8 m/s^{2}
substituting all required values we have
s = 0 + (
)
s = 0 + (
)
s = 22.22 cm