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3 years ago

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What does the second law of throdynamics state?

2 answers:

Anna71 [15]3 years ago

5 0

Explanation:

what does the second law of throdynamics state?

A. The amount of molecular disorder in the universe will always increase

B. The amount of molecular disorder in the universe will always decrease

C. The amount of molecular disorder in the universe will stay constant

Elena L [17]3 years ago

4 0

Answer:

<h2>A.</h2>

The second law of thermodynamics states that the total entropy of a system either increases or remains constant in any spontaneous process; it never decreases. ... This is because entropy increases for heat transfer of energy from hot to cold (Figure 12.9).

Explanation:

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3 years ago

Consider the following system, where F = 80 N, m = 1 kg, and M = 11 kg M m F What is the magnitude of the force with which one b

Lorico [155]

Answer:

Force exerted by the lighter block on the heavier block is 6.63 N

Explanation:

Given Data

F = 80N

m = 1kg

M = 11kg

Solution:

*We assume that there is no friction

Calculating the acceleration of the system

a = $\frac{F}{m+M}$

a = $\frac{80}{1+11}$

a = $\frac{80}{12}$

a = 6.67m $s^{-2}$

Let's write the Equation of Motion of the heavier block

$F_{1}$ = F - $F_{2}$

Ma = F - $F_{2}$

force exerted by the lighter block on the heavier block is calculated as

$F_{2}$ = F - Ma

$F_{2}$ = 80 - (11 x 6.67)

$F_{2}$ = 6.63 N

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3 years ago

A material that transmits nearly all the light in a ray because it offers little resistance to the light is

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The answer is D, transparent

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3 years ago

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Five identical cylinders are each acted on by forces of equal magnitude. Which force exerts the biggest torque about the central

elena-s [515]

Answer:

<em>From the image, the force as shown in option A will exert the biggest torque on the cylinder about its central axes.</em>

Explanation:

The image is shown below.

Torque is the product of a force about the center of rotation of a body, and the radius through which the force acts. For a given case such as this, in which the cylinders are identical, and the forces are of equal magnitude, the torque at the maximum radius away from the center will exert the maximum torque. Also, the direction of the force also matters. To generate the maximum torque, the force must be directed tangentially away from the circle formed by the radius through which the force acts away from the center. Option A satisfies both condition and hence will exert the most torque on the cylinder.

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4 years ago

In a local bar, a customer slides an empty beer mug down the counter for a refill. the height of the counter is 1.15 m. the mug

yarga [219]

<span>A. </span>Let’s say the horizontal component of the velocity is vx and the vertical is vy. <span>
Initially at t=0 (as the mug leaves the counter) the components are v0x and v0y.
<span>v0y = 0 since the customer slides it horizontally so applied force is in the x component only.

<span>The equations for horizontal and vertical projectile motion are:
x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2 </span></span></span>

Setting the origin to be the end corner of the counter so that x0=0 and y0=0, hence:

x = v0x t

y = - 1/2 g t^2

Given value are: x=1.50m and y=-1.15m (y is negative since mug is going down)

<span>1.50m = v0x t ----> v0x= 1.50/t</span>

<span>-1.15m = -(1/2) (9.81) t^2 -----> t =0.4842 s</span>

Calculating for v0x:

v0x = 3.10 m/s

<span>B. </span>v0x is constant since there are no other horizontal forces so, v0x=vx=3.10m/s

vy can be calculated from the formula:

<span>vy = v0y + at where a=-g (negative since going down)</span>

vy = -gt = -9.81 (0.4842)

vy = -4.75 m/s

Now to get the angle below the horizontal, tan(90-Ø) = -vx/vy

tan(90-Ø )= 3.1/4.75

Ø = 56.87˚<span> below the horizontal</span>

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4 years ago

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