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3 years ago

Which type of friction opposes motion?

Physics

2 answers:

Lady bird [3.3K]3 years ago

4 0

Answer:

Friction does not oppose motion, it oppose relative motion.

Explanation:

static friction opposes relative motion

RoseWind [281]3 years ago

4 0

Answer:

there are three types or friction

1) Static friction

2) Rolling Friction

3) Sliding friction

Static friction comes to end when the object starts moving(or starts motion ) so Sliding Friction and Rolling Friction opposes motion l.

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A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber

Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

$V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}$

Now calculate the bouyant force acting on the lead

$F_L = Vpg$

$F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N$

This force will act in upward direction

Gravitational force on the lead due to its mass will act in downward direction

Hence the difference of this two force

$T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N$

If V is the volume submerged in the water then bouyant force on the bobber is

$F_B=V'pg$

Equate bouyant force with the tension and gravitational force

$F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}$

Now Total volume of bobble is

$\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\$

= $\large\boxed{4.52 \%}$

7 0

3 years ago

URGENT HELP !! The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively. How much ho

IRISSAK [1]

Answer:

43.83 N

Explanation:

Given that,

The mass of an object, m = 34.4 kg

The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.

The force of static friction,

$F_s=\mu_smg\\\\F_s=0.53\times 34.4\times 9.8\\\\F_s=178.67\ N$

The force of kinetic friction,

$F_k=\mu_kmg\\\\F_k=0.40\times 34.4\times 9.8\\\\F_k=134.84\ N$

Net force acting on the object is :

F = 178.67-134.84

= 43.83 N

Hence, this is the required solution.

7 0

3 years ago

Two forces of intensities 3 N and 4 N act simultaneously on a body. If these forces have the same direction and sense, what is t

juin [17]

Answer:

If the two forces applied to an object act in the same direction ,then the resultant force acting on the object is equal to the sum of two forces: When two forces act in the same direction their effective magnitude increases

Explanation:

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leonid [27]

Answer:

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madam [21]

Answer:

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Explanation:

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3 years ago