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deff fn [24]
2 years ago
9

Can someone plzzz help me !!!!

Chemistry
2 answers:
klio [65]2 years ago
8 0

Answer:

Ability to work

Explanation:

It is correct

Archy [21]2 years ago
6 0
Answer: Ability to work




.....
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Naturally occurring neon exists as three isotopes. 90.51% is ne-20 with a mass of 19.99 amu, 0.27% is ne-21 with a mass of 20.99
gregori [183]

The atomic mass of an element is the average relative mass of its atoms as compared with an atom of carbon-12 whose mass is taken as 12. In terms of percentages of different isotopes, the average atomic mass can be determined as follows: A_{average} = ∑(p_{i}X A_{i})/100. Where, p_{i} is the percentage abundance of isotope with atomic number A_{i}.

So, average atomic mass of neon = \frac{(90.51 X 19.99) + (0.27 X 20.99) + (9.22 X 21.99)}{100} = 20.177 amu.

3 0
3 years ago
A hydrogen-filled balloon was ignited and 2.10 g of hydrogen reacted with 16.8 g of oxygen. How many grams of water vapor were f
stiks02 [169]
Hydrogen + oxygen --> water
2,1g + 16,8g = x
x = 18,9g
5 0
3 years ago
what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?
Law Incorporation [45]

A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (M1V1 = M2V2).

Utilize the titration method of M1V1 = M2V2 in view that we're given the concentrations of every compound and the quantity of KOH. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

  • M1 = initial mass
  • V1= initial volume
  • M2 = final mass
  • V2= final volume
  • (M1V1 = M2V2)
  • (0.138)(V1) = (0.205)x(26.0)
  • V2=(0.205)x(26.0)\ 0.138
  • V2 = 47.10 M/L
  • The final value of Volume needed for neutralization of nitric acid solution is  V2 = 47.10 M/L

Read more about the neutralization:

brainly.com/question/23008798

#SPJ4

4 0
1 year ago
What are the ion concentrations in a 0.12 M solution of AlCl3? A) 0.12 M Al3+ ions and 0.040 M Cl- ions B) none of the answers C
KIM [24]

Answer:

D

Explanation:

To answer this question, we will need to write the dissociation equation of aluminum trichloride.

AlCl3 ——-> Al3+ + 3Cl-

It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.

From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same

5 0
3 years ago
according to Boyles law if the initial pressure and volume of a gas were five atm for the pressure and 10 mL for the volume and
maks197457 [2]

Answer:The new volume is 5mL

Explanation:

The formular for Boyles Law is; P1 V1 = P2 V2

Where P1 = 1st Pressure   V1 = First Volume

          P2 = 2nd Pressure V2 = Second Volume

From the question; P1 = 5atm, V1 = 10ml

                                P2 = 2 x P1 (2 x 5) = 10 atm   V2 =?  

Using the Boyles Law Formular;  P1 V1 = P2 V2, we make V2 the subject of formular;  P1 V1/ P2 = V2

∴ 5 x 10/ 10 = 5

∴ V2 = 5mL

5 0
3 years ago
Read 2 more answers
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