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forsale [732]
3 years ago
5

PLEASE HELP IF YOU KNOW I WILL MARK BRAINLIEST!!! A LOT OF POINTS!!

Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
6 0
0.0039 mol/L........
I am Lyosha [343]3 years ago
3 0

Answer:

0.0039 mol/L

The molar solubility is 0.0039 mol/L, thus the common ion effect has reduced the solubility from 0.016 mol/L for Ag2SO4 in pure water to 0.0039 mol/L in the Na2SO4 solution.

Explanation:

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AlladinOne [14]
1542 is the answer. : )
7 0
3 years ago
CH3CH2OH + 302 → 2C02 + 3H2O
Colt1911 [192]

Answer:

Oxygen Gas

Explanation:

The balanced equation shows us the reactant ratio of the reaction.

This means that for every one mole of CH3CH2OH, we need 3 moles of O2 to react with it. Because we need more O2, (3x as much) than ethanol and we have the same given amount (1 mole of each), the oxygen will be the limiting reagent. (1 mole of oxygen would only require 1/3 moles of ethanol to react).

Hope this helped!

7 0
3 years ago
Calculate the molecular weight of a substance. In which the solution of this substance in the water has a concentration of 7 per
Eduardwww [97]

Answer : The molecular weight of a substance is 157.3 g/mol

Explanation :

As we are given that 7 % by weight that means 7 grams of solute present in 100 grams of solution.

Mass of solute = 7 g

Mass of solution = 100 g

Mass of solvent = 100 - 7 = 93 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=k_f\times\frac{\text{Mass of substance(solute)}\times 1000}{\text{Molar mass of substance(solute)}\times \text{Mass of water(solvent)}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure water = 0^oC

T_f = temperature of solution = -0.89^oC

K_f = freezing point constant of water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0-(-0.89))^oC=1.86^oC/m\times \frac{7g\times 1000}{\text{Molar mass of substance(solute)}\times 93g}

\text{Molar mass of substance(solute)}=157.3g/mol

Therefore, the molecular weight of a substance is 157.3 g/mol

7 0
3 years ago
Given the following information:
bonufazy [111]

Answer:

Ya'll should really practice more because things like these are easy

Explanation:

6 0
3 years ago
What is the oxidation number of HCLO4?
ki77a [65]
E.g. in H3PO4 (O, -2).
8. The sum of the oxidation states of all the atoms in a species must be equal to net charge on the species. e.g. Net Charge of HClO4 = 0, i.e. [+1(H)+7(Cl)-2<span>*4(O)] = 0.</span>
4 0
3 years ago
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