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3 years ago

9. What force is felt on a person when they 'free-fall down a large roller coaster hill?

Physics

1 answer:

spin [16.1K]3 years ago

7 0

Gravity is counteracted by centripetal force, due to acceleration, which is the force that pushes you into your seat.

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Consider a spherical planet of uniform density rho. The distance from the planet's center to its surface (i.e., the planet's rad

alisha [4.7K]

Answer:

a) $g(r) = 4\pi \cdot G \cdot \rho\cdot r$ , b) $g = 4\pi \cdot G \cdot \rho\cdot r_{P}$

Explanation:

a) The acceleration due to gravity inside the planet is:

$dg = G\cdot \frac{\rho \cdot dV}{r^{2}}$

$dg = G\cdot \frac{4\pi\cdot \rho \cdot r^{2}\,dr}{r^{2}}$

$dg = 4\pi\cdot G\cdot \rho \,dr$

$g(r) = 4\pi \cdot G \cdot \rho\cdot r$

b) The acceleration at the surface of the planet is:

$g = 4\pi \cdot G \cdot \rho\cdot r_{P}$

5 0

3 years ago

Metodo medible que no altera la composicion quimica de la materia o cuerpo?

SCORPION-xisa [38]

Answer:

Las propiedades físicas, como la dureza y el punto de ebullición, y los cambios físicos, como la fusión o la congelación, no implican un cambio en la composición de la materia.

Explanation:Creo que es correcta

3 0

3 years ago

How can we relate how gravity works to how<br> our solar system was formed?

Rzqust [24]

Answer:

gravity pulled in clouds of dust and gas. which is sometimes referred to as a nebula.

Explanation:

7 0

4 years ago

The free-body diagram of a crate is shown. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N

Umnica [9.8K]

As per given conditions there are two directions along which forces are acting

1. Net force along left direction is given as

$F_{left} = 352N + 176 N = 528 N$

2. Net force towards right direction is given as

$F_{right} = 528N + 440 N = 968 N$

now since the two forces here in opposite direction so here we will have net force given as

$F_{net} = F_{right} - F_{left}$

$F_{net} = 968 - 528$

$F_{net} = 440 N$

so here net forces must be 440 N towards right

7 0

4 years ago

Read 2 more answers

Suppose you are on a conveyor belt walkway at an airport. The walkway is moving at 0.50 m/s. You walk backward at 0.80 m/s to ha

lapo4ka [179]

Your speed is (0.5 m/s forward) + (0.8 m/s backward)

= (0.3 m/s backward) , according to witnesses
who are not on the walkway.

It doesn't matter where you're headed, or why.

4 0

3 years ago