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Alexandra [31]
3 years ago
5

PLs help I will def make you brainlist pls help both 8,9

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
5 0

Answer:

The answers are A and C

Step-by-step explanation:

Have a good day

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Evaluate (c − b)2 + a2 for a = –5, b = –2, and c = –4.
taurus [48]

(c - b)² + a²


a = -5

b = -2

c = -4


(-4 - (-2))² + (-5)²

(-4 + 2)² + (-5)²

(-2)² + (-5)²

4 + 25

29

3 0
3 years ago
The ______ of the degrees of each factor is
nasty-shy [4]

Answer:

  • B. Sum

Step-by-step explanation:

When finding the volume, we multiplied the 3 dimensions with degree of 1, 1 and 3 and got the binominal of degree 5. We summed up the degrees: 1 + 1 + 3 = 5.

  • The <u>SUM</u> of the degrees of each factor is  the degree of the product.
8 0
3 years ago
Read 2 more answers
PLLLLLLLLLLLLLEASE PLEASE PLEASE PLEASE HELLLLLPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Vika [28.1K]

Answer:

The second one (B)

Step-by-step explanation:

u don't multiply a number by the same number if u know what I mean

hope this helps <3

5 0
3 years ago
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Find the range of the data.<br><br> 4.8,5.5,4.2,8.9,3.4,7.5,1.6,3.8<br> The range is
Arada [10]

7.3 is the range

Step-by-step explanation:

The range of a set of data is the difference between the largest and smallest values.

7 0
3 years ago
Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic
Andrei [34K]

Answer:

\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

(x-a)^2+(y-b)^2+(z-c)^2=r^2

Where (x,y,z) are the points on sphere.

(a, b, c) is the center of the sphere and

r is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Here,

x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2  =2 \\z_2 =3

So, Radius is:

r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}

Therefore the equation of the sphere is:

(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

4 0
4 years ago
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