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3 years ago

How does a series circuit differ from a parallel circuit?

2 answers:

5 0

:⟹ In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component.

\pink:\implies:⟹ In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken

nika2105 [10]3 years ago

4 0

$\large \sf{Answer :- }$

$\pink:\implies$ In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component.

$\pink:\implies$ In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.

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Pretend for a day your non-dominant hand is broken and you can’t use of it. Pay attention to the activities you do every day. Yo

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I would learn to use my other hand for doing stuff

5 0

3 years ago

Hallar la distancia que recorre una movil al cabo

Kryger [21]

Answer:

Distancia, S = 136 metros

Explanation:

Dados los siguientes datos;

Aceleración, a = 3 m/s²

Velocidad inicial, u = 5 m/s

Tiempo, t = 8 segundos

Para encontrar la distancia recorrida, usaríamos la segunda ecuación de movimiento;

S = ut + ½at² Sustituyendo en la fórmula, tenemos;

S = 5 × 8 + ½ × 3 × 8²

S = 40 + 1,5 × 64

S = 40 + 96

Distancia, S = 136 metros

3 0

3 years ago

Which statement is true? A) The work done to lift an object 6 meters is greater than the gravitational potential energy it gains

inna [77]

The work required to raise an object to a height is equal to the gravitational potential energy the object gains. <em>(C)</em>

4 0

4 years ago

"Two electrons in an atom are separated by 1.4 × 10−10 m, the typical size of an atom. What is the force between them? The Coulo

Rudiy27

Answer:

$F\approx 1.17551\times 10^{-8} N$

Explanation:

In order to find the force between the two electrons, we need to use Coulomb's law. In its scalar form, the law is given by:

$F=k_c \frac{q_1*q_2}{r^2}$

Where:

$k_c=Coulomb\hspace{3}constant\approx 9\times10^{9} \frac{Nm^2}{C^2} \\q_1\hspace{3}and\hspace{3}q_2=Magnitudes\hspace{3}of\hspace{3}the\hspace{3}charges\\r=Distance\hspace{3}between\hspace{3}the\hspace{3}charges$

The electric charge of an electron is a known constant given by:

$q_e \approx -1.6 \times 10^{-19} C$

So:

$q_1=q_2=q_e \approx -1.6 \times 10^{-19} C$

Therefore, replacing the data provided in the Coulomb's law equation:

$F=(9\times 10^{9})\frac{(-1.6\times 10^{-19})*(-1.6\times 10^{-19})}{(1.4\times 10^{-10})^2} =1.175510204\times10^{-8} \approx 1.17551\times10^{-8}N$

8 0

3 years ago

From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The init

In-s [12.5K]

Answer:

a) the acceleration is -9.8 m/s^2 (gravity's acceleration), the magnitude is 9.8 m/s^2 and the direction is downwards.

The pebble is not decelerating since the magnitude of it's speed is increasing, even if it is on a negative direction.

b) after 0.5 s the pebble is 5.725 meters down. (or -5.725m from it's initial position.)

Explanation:

a) the acceleration is given only by gravity, it's the only force acting on the pebble, the slingshot only gives the pebble an initial speed.

b) To calculate the position we use the equation

y0 + v0·t + ½·g·t² = yf

replacing:

0 + (-9.0m/s) * 0.5s + 1/2 (-9.8)*0.5² = yf

-5.725 = yf

7 0

4 years ago