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Brut [27]
3 years ago
8

Pls help, science 8th grade question, #11 thx :)

Chemistry
1 answer:
Anarel [89]3 years ago
4 0
D, KOH is a concentrated Base and HCL is an acid. D is the only one that has these two.
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In one experiment 7.62 g of Fe are allowed to react with 8.67 g of S
vichka [17]

calculate moles of both reagents given and the moles of FeS that each of them would form if they were in excess  

moles = mass / molar mass  

moles Fe = 7.62 g / 55.85 g/mol  

= 0.1364 moles  

1 mole Fe produces 1 mole FeS  

Therefore 7.62 g Fe can form 0.1364 moles FeS  

moles S = 8.67 g / 32.07 g/mol  

= 0.2703 moles S  

1 mole S can from 1 moles FeS  

So 8.67 g S can produce 0.2703 moles FeS  

The limiting reagent is the one that produces the least product. So Fe is limiting.  

The maximum amount of FeS possible is from complete reaction of all the limiting reagent.  

We have already determined that the Fe can form up to 0.1364 moles of FeS, so this is max amount of FeS you can get.  

Convert to mass

hope this helps :)

4 0
3 years ago
Which of the following situations most likely indicates the lowest relative humidity? situation A situation B situation C situat
statuscvo [17]

Answer:

Situation B indicates the significant depression of temperature in the wet bulb thermometer.

Answer Statement: B

Explanation:

Temperature Depression & Relative Humidity

As we can see that there are four cases to study the affect of relative humidity  on the temperature measured by thermometers, set up in different situations i.e., one is dry and the other one is dry.

As situation B describes the most admissible temperature drop in the wet bulb thermometer with a relative humidity of approximately 17% i.e., this can be the appropriate to reflect the lowest relative humidity with a fact that the relative humidity reduces with a larger count of temperature depression. Whereas, the relative humidity for other situations are resulting much higher.

5 0
4 years ago
Read 2 more answers
What is the concentration of pb 2 ions in a solution prepared by adding 5. 00 g of lead(ii) iodide to 500. ml of 0. 150 m ki? [
sashaice [31]

37.1×10−8M is the concentration of pb 2 ions in a solution prepared by adding 5. 00 g of lead(ii) iodide to 500. ml of 0. 150 m ki? [ k sp(pbi 2) =1. 4 × 10 –8] by common ion effect.

A phenomenon known as the "common ion effect" allows for the modification of a salt's molar solubility by adding another salt in which one ion dissociates in solution and maintains equilibrium with the undissociated salt.

The term "common-ion effect" describes the reduction in solubility of an ionic precipitate caused by the addition of a soluble molecule that shares an ion with the precipitate to the solution. Le principle for the equilibrium response of ionic association/dissociation leads to this behavior.

To learn more about the "common-ion effect" please visit-
brainly.com/question/13194653
#SPJ4

4 0
2 years ago
Which arrow or arrows represent reactions that demonstrate a conservation of mass and energy? Explain your answer
Kruka [31]

Answer:

i need a picture of ur question

Explanation:

7 0
3 years ago
Aluminum bromide and chlorine gas react to<br> form aluminum chloride and bromine gas.
Margarita [4]

Answer:

ok

Explanation:

4 0
3 years ago
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