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Paraphin [41]
3 years ago
6

Write a chemical formula that shows 3 molecules of water.

Chemistry
2 answers:
Lelechka [254]3 years ago
5 0
3H2O is formula for 4 molecules of washer
asambeis [7]3 years ago
3 0

3H₂O is formula for 4 molecules of water

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Aluminium metal will readily react with water at room temperature to form aluminium hydroxide and hydrogen
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Cl2 reacts with the element Sr to form an ionic compound. Based on periodic properties, identify a molecule, X2, that is likely
Leto [7]

Answer:

The bromine molecule, Br2 will likely react with Sr in a similar way to chlorine molecule, Cl2.

Explanation:

Chlorine belongs to group 7 of the periodic table. Elements in this group are known as halogens. Its molecule has the formula Cl2. The next element in the group after chlorine is bromine. Its molecule has a formula Br2. It has similar properties as chlorine, therefore, it would react with Strontium in a similar way to chlorine.

Elements belonging to the same group of the periodic the table have similar chemical properties as they contain the same number of valence electrons. Chlorine and Bromine both belong to group 7 of the periodic table and each have seven valence electrons. They both react with metals to form salts even though reaction with chlorine is more vigorous as it is more reactive than bromine. They both form negatively-charged ions with a charge of -1.

Reaction of Strontium with the halogens:

With chlorine: Sr + Cl2 ---> SrCl2

With bromine: Sr + Br2 ---> SrBr2

The salts formed are both crystalline salts with high melting and boiling points.

3 0
4 years ago
Why does temperature increase with altitude through the stratosphere?
KIM [24]

Answer:

The air molecules are closer together in the upper stratosphere.

Explanation:

8 0
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Ten kilograms of R-134a fill a 1.595-m3 weighted piston-cylinder device at a temperature of −26.4°C. The container is now heated
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Explanation:

The given data is as follows.

    Mass of refrigerant, m = 10 kg

  Volume of the refrigerant, V = 1.595 m^{3}

Formula for specific volume of the refrigerant is as follows.

        v = \frac{V}{m}

           = 0.1595 m^{3}/kg

So, at -26.4^{o}C specific volume will be within v_{f} and v_{g} and pressure is constant.

The fluid will be in super-heated state at temperature 100^{o}C and at T = -26.4^{o}C pressure 1 bar = 0.1 MPa.

According to super-heated tables, the specific volume is v = 0.30138 m^{3}/kg.

Hence, the final volume will be calculated as follows.

               V_{f} = v \times m

                         = 0.30138 m^{3}/kg \times 10 kg

                         = 3.0138 m^{3}

Thus, we can conclude that final volume of the R-134a is 3.0138 m^{3}.

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Answer:

I think the answer is A) repeatedly testing the solubility at various temperatures

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