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melamori03 [73]
2 years ago
6

Match the use of the magnetic field to its respective description.​

Engineering
1 answer:
Vesna [10]2 years ago
6 0

oooExplanation:

oooooooooooooooo

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A two-stroke CI. engine delivers 5000 kWwhile using 1000 kW to overcome friction losses. It consumes 2300 kg of fuel per hour at
Lady_Fox [76]

Answer:

(a) Indicating power(IP)=6000 KW

(b)   \eta_{mech}=0.833

(c) Consumption of air per hour =46000 kg/hr

(d) \eta_{BPth}=0.1865

Explanation:

Break power(BP) =5000 KW

Friction power(FP)=1000 KW

Consumption of fuel per hour=2300 kg/hr

CV=42000 KJ/kg

We know that

Indicating power(IP)=Break power(BP)+Friction power(FP)

⇒IP=5000+1000 KW

  IP=6000 KW

(a)

Indicating power(IP)=6000 KW

(b)

Mechanical efficiency  \eta_{mech}=\dfrac{BP}{IP}

 \eta_{mech}=\dfrac{5000}{6000}      

  \eta_{mech}=0.833

(c)

Air fuel ratio=\dfrac{mass \ of \ air}{mass \ of \ fuel}

consumption of air per hour=20\times2300 kg/hr

So consumption of air per hour =46000 kg/hr

(d)

Break thermal efficiency  \eta_{BPth}=\dfrac{IP}{\dot{m_f}\times CV}

\dot{m_f}=\dfrac{2300}{3600}  

                      =0.638 kg/s

\eta_{BPth}=\dfrac{5000}{{0.638}\times 42000}

\eta_{BPth}=0.1865

 

5 0
3 years ago
An insulated tank having a total volume of 0.6 m3 is divided into two compartments. Initially one compartment contains 0.4 m3 of
IRISSAK [1]

Answer:

a. The final temperature is 69.8°C

b. The final pressure is 2.67bar

c. The amount of entropy produced is 0.38568kJ/K

Explanation:

Pls, check the attached files for detail step by step explanation as typing the solution here can not be explicit.

5 0
3 years ago
The acceleration of a point is given. a = 20 t m/s2 When t=0, s = 50 m and v = -8 m/s. What are the position and velocity of the
lidiya [134]

Answer:

v=82 m/s

s=116m

Explanation:

a=20t

\frac{\mathrm{d} v}{\mathrm{d} t}=20t\\\int\limits dv =\int(20t) dt\\v={10}t^2+c

using condition given at t=0

-8=10\times 0^2 +c

c=-8

now equation becomes

v=10t²-8

v at t= 3s  v=82 m/s

again

\frac{\mathrm{d} s}{\mathrm{d} t}=10t^2-8

ds=(10t^2-8)dt\\\int\limits ds =\int(10t^2-8) dt\\s=\frac{10}{3} t^2-8t+b

now using condition given s=50 at t=0

b=50

now equation becomes

s=\frac{10}{3}t^3-8t+50

calculating s at t=3s

s=116m

6 0
2 years ago
Their game off badminton is always on Tuesday
igomit [66]

Ok? is this a question or what?

5 0
2 years ago
Today I meant to look for my missing watch, but I could never find the time.
xxMikexx [17]

Answer:

haha i get it

Explanation:

5 0
2 years ago
Read 2 more answers
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