Hey there!
I attached a screenshot of my chemistry notes from this year on equilibrium constants in particular. Feel free to reference this in the future if you wish.
Based on the information in my attachment, you could construct your constant like this:
![K_{eq} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}](https://tex.z-dn.net/?f=%20K_%7Beq%7D%20%3D%20%20%5Cfrac%7B%5BCaO%5D%5BCO_%7B2%7D%5D%7D%7B%5BCaCO_%7B3%7D%5D%7D%20)
I don't think it matters which order your reactants or products are in as long as you have them on the top and bottom where they need to be, so your answer will be B.
Hope this helped you out! :-)
Answer:
22.4L
Explanation:
The following data were obtained from the question:
P = 1atm
T = 273K
n = 1mole
R = 0.08206 L∙atm/mol∙K
V =?
PV = nRT
V = nRT/P
V = (1 x 0.08206 x 273)/1
V = 22.4L
Answer:
They increases the distance of applied force(torque)as well as they change the strenght or direction of a force(90 angle work).
Explanation:
Answer:
- From octane: 
- From ethanol: 
Explanation:
Hello,
At first, for the combustion of octane, the following chemical reaction is carried out:

Thus, the produced mass of carbon dioxide is:

Now, for ethanol:


Best regards.