Answer:
independent variable - the thing you change
dependent variable - the thing you measure
control variables - the things you keep the same
<span>There are few main factors affecting the atomic radii, the outermost electrons and the protons in the nucleus and also the shielding of the internal electrons. I would speculate that the difference in radii is given by the electron clouds since the electrons difference in these two elements is in the d orbital and both has at least 1 electron in the 4s (this 4s electron is the outermost electron in all the transition metals of this period). The atomic radio will be mostly dependent of these 4s electrons than in the d electrons. Besides that, you can see that increasing the atomic number will increase the number of protons in the nucleus decreasing the ratio of the atoms along a period. The Cu is an exception and will accommodate one of the 4s electrons in the p orbital.
</span><span>Regarding the density you can find the density of Cu = 8.96g/cm3 and vanadium = 6.0g/cm3. This also correlates with the idea that if these two atoms have similar volume and one has more mass (more protons; density is the relationship between m/V), then a bigger mass for a similar volume will result in a bigger density.</span>
Answer: capillary action
Explanation: it occurs when the adhesion forces (attraction between two surfaces or substances) in the liquid are stronger than the cohesion forces (attraction between the same molecule)
To measure the density of the stone placed in a graduated cylinder let us follow these steps bellow
- Measure the volume of water poured into a graduated cylinder
- Place the object in the water and remeasure the volume.
- The difference between the two volume measurements is the volume of the object.
- Divide the mass by the volume to calculate the density of the object.
<em>We know that the formula for density is given as </em>
Given data
Mass = 8gram
Initial Volume of water in cylinder = 25mL
Final Volume of water in cylinder = 29mL
Hence the volume of the rock = 29-25 = 4mL
Therefore the density of the rock = 8/4 = 2 g/mL
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Buoyancy is considered a physical property. It is a type of physical property because it is related to the density and weight of the item, which are both physical.