The solution would be made by dissolving 4 grams NaOH in .5 Liters of H2O
Colligative
properties calculations are used for this type of problem. Calculations are as
follows:<span>
ΔT(freezing point) = (Kf)(molality)
ΔT(freezing point)
= 1.86 °C kg / mol (molality)
</span>Tf - 102.08 = 1.86m
Tf = 1.86m + 102.08
The concetration of the solution is needed in order to obtain a specific value.
Answer:
Gravity
Explanation:
An object's weight is dependent on its mass and how strongly gravity pulls on it. The strength of gravity depends on how far away one object is from another. That's why the same object weighs different amounts on different planets.
<span>C = 4.18
delta T = 24.25 - 23.16 = 1.09
mol = 0.070L * 0.185M = 0.01295
m = d*v = 1.00*(0.070+0.070) = 0.14g
So, delta H = q/mol HCl = [mC(deltaT)]/mol HCl = (0.14*4.18*1.09)/(0.01295) = 49.3 kJ</span>
