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Aleksandr-060686 [28]
3 years ago
10

3.

Physics
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

A. Condensation B. Freezing. C. condensation (not sure) D. Sublimation E. Evaporation. F Evaporation (not sure)

Hope it heps:)

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With what minimum speed must you toss a 200 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release
Brut [27]
When they say use energy, you want to use

Total energy = potential energy + kinetic energy = mgh + 1/2mv²

I assume you mean 200 g ball,

so, we know the total distance traveled is going to be 13 - 1.3 = 11.7 m

If the ball just makes it to the top ( 13 m ) , then the ball will stop moving and the kinetic energy will be 0,

therefore, the potential energy at the top will be the total energy of the system = mgh

from this, we say that mgh = 1/2mv² solve for v

<span> v = sqrt (2gh) = 15.2 m/s </span>
8 0
3 years ago
Which states of matter are significantly compressible?
andreev551 [17]
Hello.


The gaseous state is the more compressible state, because it has the volume of its container.

The liquid state is virtually incompressible, and the solid state compression is very small.

The plasma is another state that has high compression, but in this case the matter is not bound(we don't have the proton in the core of the atom)
5 0
3 years ago
A skydiver has jumped out of a plane and is falling faster and faster. what forces are present in this situation
kompoz [17]
Gravity and air resistance 

i took the test and got 100%
5 0
3 years ago
a car travels 10 miles east in 30 minutes. what is its velocity in miles per hour. what is its velocity in miles per hour?
nika2105 [10]

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popu

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8 0
3 years ago
A 7 kg ball is moving at a constant speed of 5 m/s. A force of 300 N is applied to the ball for 4 s. The new speed of the ball i
olasank [31]

Answer:

The new speed of the ball is 176.43 m/s

Explanation:

Given;

mass of the ball, m = 7 kg

initial speed of the ball, u = 5 m/s

applied force, F = 300 N

time of force action on the ball, t = 4 s

Apply Newton's second law of motion;

F = ma = \frac{m(v-u)}{t}\\\\m(v-u) = Ft\\\\v-u = \frac{Ft}{m}\\\\v =  \frac{Ft}{m} + u

where;

v is new speed of the ball

v =  \frac{Ft}{m} + u\\\\v =\frac{300*4}{7} + 5\\\\v = 176.43 \ m/s

Therefore, the new speed of the ball is 176.43 m/s

8 0
3 years ago
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