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3 years ago

3.

Physics

1 answer:

Lana71 [14]3 years ago

6 0

Answer:

A. Condensation B. Freezing. C. condensation (not sure) D. Sublimation E. Evaporation. F Evaporation (not sure)

Hope it heps:)

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The diagram below shows four positions of the Moon. Which position produces the highest possible tides?

suter [353]

It is position when Moon is between Earth and Sun. In this case gravitational forces of both Moon and Sun pull water in same direction and magnitude of gravitational force is greatest. When Moon and Sun are on opposite sides of Earth gravitational force pulls water in two opposite directions and magnitude of gravitational force is smallest and tide is lower. When Moon is in position that is shown as above or below Earth than magnitude of gravitational force is between those two already mentioned.

6 0

3 years ago

Read 2 more answers

Howard woke up and turned on his lamp. Also, he turned on the television to hear the weather. He walked to the bathroom to

Hoochie [10]

Answer: 5 words >>>> he is living a life

Explanation:

4 0

3 years ago

n a local coffee shop, a customer slides her empty nitro cold brew downthe counter for a refill. The barista is distracted, and

Marta_Voda [28]

Answer:

5 m/s

Explanation:

Horizontal distance traveled, x = 2 m

vertical distance traveled, y = 4/5 m

Let the speed of cup as it leaves the counter is v and it takes time t to hit the ground.

Use second equation of motion in vertical direction

$y = ut+\frac{1}{2}at^{2}$

Here acceleration in vertical direction is 9.8 m/s^2.

So,

$\frac{4}{5} = 0+\frac{1}{2}\times9.8t^{2}$

t = 0.4 second

Now in horizontal direction the acceleration in zero.

Horizontal distance = horizontal velocity x time

x = v t

2 = v (0.4)

v = 5 m/s

Thus, the horizontal velocity of cup as it leaves the counter is 5 m/s.

4 0

3 years ago

the cyclist has a mass of 50kg and is acceleratiing at 0.9m/s^2. What is the size of the unbalanced force F acting on the cyclis

stiv31 [10]

Answer:

45 N

Explanation:

The question can be solved by using Newton's second law:

F = ma

where

F is the net (unbalanced) force on the cyclist

m is the mass of the cyclist

a is his acceleration

In this problem:

m = 50 kg

$a=0.9 m/s^2$

Therefore, the unbalanced force is

$F=(50)(0.9)=45 N$

4 0

4 years ago

A 74-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.56 m,

Reptile [31]

Answer:

Work done, W = 1.44 kJ

Explanation:

Given that,

Mass of boy, m = 74 kg

Initial speed of boy, u = 1.6 m/s

The boy then drops through a height of 1.56 m

Final speed of boy, v = 8.5 m/s

To find,

Non-conservative work was done on the boy.

Solution,

The work done by the non conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.

$W=\dfrac{1}{2}m(v^2-u^2)+(0-mgh)$

$W=\dfrac{1}{2}m(v^2-u^2)-mgh$

$W=\dfrac{1}{2}\times 74\times (8.5^2-1.6^2)-74\times 9.8\times 1.56$

W = 1447.21 Joules

W = 1.44 kJ

Therefore, the non conservative work done on the boy is 1.44 kJ.

4 0

3 years ago