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<u>Answer:</u> The mass of NaBr that can be produced is 6.3 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For HBr:</u>
Given mass of HBr = 17 g
Molar mass of HBr = 81 g/mol
Putting values in equation 1, we get:
- <u>For NaOH:</u>
Given mass of NaOH = 2.44 g
Molar mass of NaOH = 40 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of HBr and NaOH follows:
By Stoichiometry of the reaction:
1 mole of NaOH reacts with 1 mole of HBr
So, 0.061 moles of NaOH will react with = of HBr
As, given amount of HBr is more than the required amount. So, it is considered as an excess reagent.
Thus, NaOH is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of NaOH produces 1 mole of NaBr
So, 0.061 moles of NaOH will produce = of carbon dioxide
Now, calculating the mass of NaBr from equation 1, we get:
Molar mass of NaBr = 103 g/mol
Moles of NaBr = 0.061 moles
Putting values in equation 1, we get:
Hence, the mass of NaBr that can be produced is 6.3 grams