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coldgirl [10]
3 years ago
7

Calculate the magnitude of the normal force on a 15.2 kg block in the following circumstances. (Enter your answers in N.) (a) Th

e block is resting on a level surface. __________ N (b) The block is resting on a surface tilted up at a 35.8 angle with respect to the horizontal. __________ N (c) The block is resting on the floor of an elevator that is accelerating upward at 3.53 m/s ___________ N (d) The block is on a level surface and a force of 155 N is exerted on it at an angle of 35.8 below the horizontal. _________N
Physics
1 answer:
Keith_Richards [23]3 years ago
8 0

Answer:

149.112\ \text{N}

120.94\ \text{N}

302.77\ \text{N}

58.44\ \text{N}

Explanation:

m = Mass of block = 15.2 kg

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

\theta = Angle

a = Acceleration

F = Applied force

Normal force is given by

N=mg\\\Rightarrow N=15.2\times 9.81\\\Rightarrow N=\boldsymbol{149.112\ \mathbf{N}}

\theta=35^{\circ}

N=mg\cos\theta\\\Rightarrow N=15.2\times 9.81\times \cos35.8^{\circ}\\\Rightarrow N=\mathbf{120.94\ N}

a=3.53\ \text{m/s}^2

N=m(g+a)\\\Rightarrow N=15.2(9.81+3.53)\\\Rightarrow N=\boldsymbol{302.77\ \mathbf{N}}

F=155\ \text{N}

N=mg-F\sin35.8^{\circ}\\\Rightarrow N=15.2\times 9.81-155\sin35.8^{\circ}\\\Rightarrow N=\boldsymbol{58.44\ \mathbf{N}}

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