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3 years ago

What statements are true???

Physics

1 answer:

tatiyna3 years ago

8 0

Answer:

Explanation:

opposite charges attract

same charges repel

neutral charges don't attract or repel

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In simple harmonic motion, the speed is greatest at that point in the cycle whenA) the magnitude of the acceleration is a maximu

hram777 [196]

Answer:

C) the magnitude of the acceleration is a minimum.

Explanation:

As we know that ,the general equation of the simple harmonic motion given as

The displacement x given as

x=X sinω t

Then the velocity v will become

v= X ω cosωt

The acceleration a

a= - X ω² sinω t

The speed of the particle will be maximum when cosωt will become 1 unit.

It means that sinωt will become zero.So acceleration and displacement will be minimum.

Therefore when speed is maximum then acceleration will be minimum.

At the mean position the speed of the particle is maximum that is why kinetic energy also will be maximum and the potential energy will be minimum.

Therefore option C is correct.

4 0

3 years ago

What measurment is used for the diameter of wires

faust18 [17]

Wire gauge is the measurement for diameter wires

5 0

4 years ago

Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. A particle with charge q i

sergejj [24]

Answer: in this question, the only charge in the cavity is Q. Inside the conducting spherical shell, the electric field is zero.

While outside the shell, the electric field is given by: k(q + Q)/r²

Where;

K= is a constant which is given as, 8.99 x 10^9 N m² / C².

Q= source charge which creates the electric field

q= is the test charge which is used to measure the strength of the electric field at a given location.

r= is the radius

Explanation: Inside the conducting spherical shell, the electric field is zero since the Electric field vanishes everywhere inside the volume of a good conductor.

8 0

3 years ago

A hoop, a solid cylinder, a spherical shell, and a solid sphere are placed at rest at the top of an inclined plane. All the obje

iogann1982 [59]

Answer:

Solid sphere will reach first

Explanation:

When an object is released from the top of inclined plane

Then in that case we can use energy conservation to find the final speed at the bottom of the inclined plane

initial gravitational potential energy = final total kinetic energy

$mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$

now we have

$I = mk^2$

here k = radius of gyration of object

also for pure rolling we have

$v = R\omega$

so now we will have

$mgh = \frac{1}{2}mv^2 + \frac{1}{2}(mk^2)(\frac{v^2}{R^2})$

$mgh = \frac{1}{2}mv^2(1 + \frac{k^2}{R^2})$

$v^2 = \frac{2gh}{1 + \frac{k^2}{R^2}}$

so we will say that more the value of radius of gyration then less velocity of the object at the bottom

So it has less acceleration while moving on inclined plane for object which has more value of k

So it will take more time for the object to reach the bottom which will have more radius of gyration

Now we know that for hoop

$mk^2 = mR^2$

k = R

For spherical shell

$mk^2 = \frac{2}{3}mR^2$

$k = \sqrt{\frac{2}{3}} R$

For solid sphere

$mk^2 = \frac{2}{5}mR^2$

$k = \sqrt{\frac{2}{5}} R$

So maximum value of radius of gyration is for hoop and minimum value is for solid sphere

so solid sphere will reach the bottom at first

7 0

3 years ago

N/a<br>n/a<br>nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

disa [49]

Answer:

hiii

Can I get the Brainiest?

7 0

3 years ago